6> 0. I know you can d [ Select ] e kernel trick. 1/b ution. Many distributions can be s) times the kernel (the terms that Step 1: We first need to broken into a normalizing a cannot be separated fron e^(-x/b) Here, you recognize that [Select ] is the kernel of an exponential distribution f(x) = de-A, and the support of an exponential distribution is (0, oo) --- that is, the limits of integration here. Step 2: Use the distribution to figure out what the normalizing constant would be. In the exponential distribution, X is the normalizing constant. In the kernel you identified above,1 = [ Select ] [ Select] 1/b divide by the normalizing constant, and obtain the integrand You rearrange the terms in your integral so that it has the form e^(-x/b) c f(x) dæ where f(x) is a proper exponential distribution and c is some constant. Then c = [ Select ] Step 3: Thus, you multiply and divide by the normalizing constant, and obtain the integrand [ Select ] You rearrange the terms in your integral so that it has the form [ Select ] roper exponential distribution and c is some constant. ab (1/b) * e^(-x/b) Choose the other answer. It's right. Step 4: Since f(x) is the pdf of an exponential distribution, o f(x)dx = 1. Thus, ae /b dx = (your expression for c) %3D Step 3: Thus, you multiply and divide by the normalizing constant, and obtain the integrand [ Select ] You rearrange the terms in your integral so that it has the form c f(x)dx where f(x) is a proper exponential distribution and c is some constant. Then c = [ Select ] [ Select ] a/b Step 4: Si a*b ential distribution, f(x)dx = 1. Thus, S ae Step 4: Since f(x) is the pdf of an exponential distribution, So f(x)da = 1. Thus, ae a/b dx = (your expression for c) %3D
6> 0. I know you can d [ Select ] e kernel trick. 1/b ution. Many distributions can be s) times the kernel (the terms that Step 1: We first need to broken into a normalizing a cannot be separated fron e^(-x/b) Here, you recognize that [Select ] is the kernel of an exponential distribution f(x) = de-A, and the support of an exponential distribution is (0, oo) --- that is, the limits of integration here. Step 2: Use the distribution to figure out what the normalizing constant would be. In the exponential distribution, X is the normalizing constant. In the kernel you identified above,1 = [ Select ] [ Select] 1/b divide by the normalizing constant, and obtain the integrand You rearrange the terms in your integral so that it has the form e^(-x/b) c f(x) dæ where f(x) is a proper exponential distribution and c is some constant. Then c = [ Select ] Step 3: Thus, you multiply and divide by the normalizing constant, and obtain the integrand [ Select ] You rearrange the terms in your integral so that it has the form [ Select ] roper exponential distribution and c is some constant. ab (1/b) * e^(-x/b) Choose the other answer. It's right. Step 4: Since f(x) is the pdf of an exponential distribution, o f(x)dx = 1. Thus, ae /b dx = (your expression for c) %3D Step 3: Thus, you multiply and divide by the normalizing constant, and obtain the integrand [ Select ] You rearrange the terms in your integral so that it has the form c f(x)dx where f(x) is a proper exponential distribution and c is some constant. Then c = [ Select ] [ Select ] a/b Step 4: Si a*b ential distribution, f(x)dx = 1. Thus, S ae Step 4: Since f(x) is the pdf of an exponential distribution, So f(x)da = 1. Thus, ae a/b dx = (your expression for c) %3D
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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