A foundation is 3 mx 2 m in plan. Given: Df= 1.5 m, o'= 25°, c'= 70 kN/m². With General Bearing Capacityequation and FS = 3 assmuming general shear failure in soil, determine the net allowable load that thefooting can carry.a) NOTE: Due to drought, groundwater level has been lowered down to a depth of 1.5mfrom the ground surface.b) Net allowable load that the footing can carry using general bearing capacity equationand F.S.=3 assuming general shear failure in soil.c) Ultimate bearing capacity (qu) using prakash and saran theory with eB=0.3m andeL=0.5m.y = 17 kN/m1 m1.5 mGroundwater level3 m x 2 mYut = 19.5 kN/m

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A foundation is 3 mx 2 m in plan. Given: Dr= 1.5 m, o'= 25°, c'= 70 kN/m². With General Bearing Capacity equation and FS = 3 assmuming general shear failure in soil, determine the net allowable load that the footing can carry. %3D

A foundation is 3 mx 2 m in plan. Given: Dr= 1.5 m, o'= 25°, c'= 70 kN/m². With General Bearing Capacity equation and FS = 3 assmuming general shear failure in soil, determine the net allowable load that the footing can carry. %3D

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Load and resistance factor design

Load and resistance factors design (LRFD), also known as Limit state design (LSD), refers to the design method used in building engineering. A boundary condition is a condition of a structure where it can no longer meet the relevant design requirements. The condition may refer to the load level or other actions on the structure, while the terms refer to the integrity of the structure, suitability for use, durability, or other design requirements. A structure designed for LRFD is limited to keeping track of all possible actions during its design time and is always ready for use, with the appropriate level of reliability in each boundary condition. LRFD-based construction codes clearly define the appropriate levels of reliability in their instructions.

Question

A foundation is 3 mx 2 m in plan. Given: Df= 1.5 m, o'= 25°, c'= 70 kN/m². With General Bearing Capacity
equation and FS = 3 assmuming general shear failure in soil, determine the net allowable load that the
footing can carry.
a) NOTE: Due to drought, groundwater level has been lowered down to a depth of 1.5m
from the ground surface.
b) Net allowable load that the footing can carry using general bearing capacity equation
and F.S.=3 assuming general shear failure in soil.
c) Ultimate bearing capacity (qu) using prakash and saran theory with eB=0.3m and
eL=0.5m.
y = 17 kN/m
1 m
1.5 m
Groundwater level
3 m x 2 m
Yut = 19.5 kN/m

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A continuous footing is to be designed to carry a wall load of 7 kips/ft. The soil shear strength parameters are as follows: Sy = 700 psf and 0 = 0-deg. Foundation Depth, D = 2.5 ft and Soil Unit Weight, y = 110 Ib/ft°. Unit weight of concrete = 150 lb/ft°. Determine the necessary footing width to carry the above column load if a factor of safety of 2.5 is desired. The water table is at great depth and therefore, has no impact on bearing capacity. a) Ultimate Bearing Capacity of the footing (in Ib/ft) using Terzaghi's equation = .(Report to nearest whole number) b) Allowable Bearing Capacity of the footing (in Ib/ft-) using Terzaghi's equation = ...(Report to nearest whole number) c) Footing width (in ft) required = (Report to the nearest two decimals)
Please allow for all steps
Use Terzaghi's equation and Terzaghi's Table
Use Terzaghi equation and Terzaghi table.
Assume γ = 105 pcf, D= 4 ft,Q = 2000 lb , F.S = 3, Φ = 34° . Determine the size of the footing.
Example 5 A square foundation (B * B) has to been constructed. Assume yd = 16.5 kN/m³, Ysat = 18.55 kN/m, o' = 34°, Dr = 1.22m and water table at 0.61m and the gross allowable load, Qall with FS = 3 is 667.2 kN Determine the size of the footing, (use Vesic bearing capacity factors).
2. The column load of a square foundation (Figure 1) is given. If the depth of foundation D= 4 ft, 0=30°, and c = 0. Using Terzaghi's bearing capacity equation and FS = 2.5, determine the proper size of the footing. D.L. = 80 kip L.L. = 60 kip qult = 1.3 c N. + qN, + 0.4 y B N, Figure 1 TABLE 2.1 Terzaghi's Bearing Capacity Factors-Eqs. (2.32), (2.33), and (2.34) N. N, N. N. N, N. N, N, Ysoil = 118 pcf 2 ft W.T 1.00 0.00 17 14.60 0.01 18 15.12 1.22 0.04 19 | 16.57 6.62 1.35 0.06 20 | 17.69 1.49 0.10 21 | 18.92 |1.64 0.14 22 20.27 1.81 0.20 23 21.75 2.00 0.27 24 23.36 2.21 0.35 25 25.13 2.44 0.44 26 27.09 9.61 2.69 0.56 27 29.24 5.70 5.45 2.18 34 2.59 35 36 52.64 57.75 36.50 38.04 D; = 4m 6.00 1.1 6.04 41.44 45.41 6.30 6.70 3.07 63.53 47.16 54.36 3.64 4.31 38 5.09 39 70.01 77.50 85.97 95.66 106.81 65.27 78.61 95.03 3 7.44 37 53.80 8.26 9.19 61.55 70.61 4 6.97 5 7.34 3m x2m 6. 7.73 10.23 6.00 40 81.27 115.31 11.40 12.72| 8.34 8.15 7.08 41 93.85 140.51 171.99 211.56 8 8.60 42 119.67…