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A square footing of 1 m is located at a depth 1.5 m below the ground surface. The soil properties are: c' = 0, ' = 40°, y = 16.7 kN/m³, Ysat = 20 kN/m³. Using Terzaghi's bearing capacity factors calculate the ultimate bearing capacity: (a) The water table is well below the foundation level, (b) The water table is at the ground surface. Given Kpy= (8² - 4' + 3.8)tan² (60+ N₁ = (N − 1) cot Na a² 2 cos²(45° +012) $/) where a = (0.75-4/2)tan Ny tan K PY = 2 cos² a₁ = entano, n = (0.75л — ø/2)

A square footing of 1 m is located at a depth 1.5 m below the ground surface. The soil properties are: c' = 0, ' = 40°, y = 16.7 kN/m³, Ysat = 20 kN/m³. Using Terzaghi's bearing capacity factors calculate the ultimate bearing capacity: (a) The water table is well below the foundation level, (b) The water table is at the ground surface. Given Kpy= (8² - 4' + 3.8)tan² (60+ N₁ = (N − 1) cot Na a² 2 cos²(45° +012) $/) where a = (0.75-4/2)tan Ny tan K PY = 2 cos² a₁ = entano, n = (0.75л — ø/2)

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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A square footing of 1 m is located at a depth 1.5 m below the ground surface. The soil properties are: c' = 0, ' = 40°, y = 16.7 kN/m³, Ysat = 20 kN/m³. Using Terzaghi's bearing capacity factors calculate the ultimate bearing capacity: (a) The water table is well below the foundation level, (b) The water table is at the ground surface. Given Kpy= (8² - 4' + 3.8)tan² (60+ N₁ = (N − 1) cot Na a² 2 cos²(45° +012) $/) where a = (0.75-4/2)tan Ny tan K PY = 2 cos² a₁ = entano, n = (0.75л — ø/2)
Transcribed Image Text:A square footing of 1 m is located at a depth 1.5 m below the ground surface. The soil properties are: c' = 0, ' = 40°, y = 16.7 kN/m³, Ysat = 20 kN/m³. Using Terzaghi's bearing capacity factors calculate the ultimate bearing capacity: (a) The water table is well below the foundation level, (b) The water table is at the ground surface. Given Kpy= (8² - 4' + 3.8)tan² (60+ N₁ = (N − 1) cot Na a² 2 cos²(45° +012) $/) where a = (0.75-4/2)tan Ny tan K PY = 2 cos² a₁ = entano, n = (0.75л — ø/2)
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