A force F = (1.70 N) i + (5.70 N)j+(7.80 N) k acts on a 5.50 kg mobile object that moves from an initial position of d = (7.50 m) i+(9.10 m)j+ (8.80 m) k to a final position of d f = (4.90 m) î + (6.00 m)j + (9.40 m) k in 2.90 s. Find (a) the work done on the %3D %3D %3D object by the force in the 2.90 s interval, (b) the average power due to the force during that interval, and (c) the angle between vectors d, and d .

A force F = (1.70 N) i + (5.70 N)j+(7.80 N) k acts on a 5.50 kg mobile object that moves from an initial position of d = (7.50 m) i+(9.10 m)j+ (8.80 m) k to a final position of d f = (4.90 m) î + (6.00 m)j + (9.40 m) k in 2.90 s. Find (a) the work done on the %3D %3D %3D object by the force in the 2.90 s interval, (b) the average power due to the force during that interval, and (c) the angle between vectors d, and d .

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Concept explainers

Static and Kinetic Friction

Kinetic friction comes into existence when there are moving surfaces means in other words we can say that the force which comes into existing between moving surfaces is known as kinetic friction.

Question

A force F = (1.70 N) i + (5.70 N)j+(7.80 N) k acts on a 5.50 kg mobile object that moves from an initial position of
d = (7.50 m) i+(9.10 m)j+ (8.80 m) k to a final position of d f = (4.90 m) î + (6.00 m)j + (9.40 m) k in 2.90 s. Find (a) the work done on the
%3D
%3D
%3D
object by the force in the 2.90 s interval, (b) the average power due to the force during that interval, and (c) the angle between vectors d, and d .

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