The problem involves a 4.5 kg body moving along the positive x-axis. The only force acting on it has an x-component given by \( F_x = -7x \, \text{N} \), where \( x \) is in meters. When the body is at \( x = 1.5 \, \text{m} \), its velocity is \( 8.8 \, \text{m/s} \).**Questions:**1. (a) What is the velocity of the body at \( x = 5.0 \, \text{m} \)? - Input box for the number and a dropdown for units.2. (b) At what positive value of \( x \) will the body have a velocity of \( 5.8 \, \text{m/s} \)? - Input box for the number and a dropdown for units.

Answered: Image /qna-images/answer/70c5e044-10be-4992-a237-5a3c1604de83.jpg

The only force acting on a 4.5 kg body as it moves along the positive x axis has an x component Fx = - 7x N, where x is in meters. The velocity of the body at x = 1.5 m is 8.8 m/s. (a) What is the velocity of the body at x = 5.0 m? (b) At what positive value of x will the body have a velocity of 5.8 m/s? (a) Number i Units (b) Number i Units

The only force acting on a 4.5 kg body as it moves along the positive x axis has an x component Fx = - 7x N, where x is in meters. The velocity of the body at x = 1.5 m is 8.8 m/s. (a) What is the velocity of the body at x = 5.0 m? (b) At what positive value of x will the body have a velocity of 5.8 m/s? (a) Number i Units (b) Number i Units

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

The only force acting on a 3.6 kg body as it moves along the positive x axis has an x component Fx = - 5x N, where x is in meters. The velocity of the body at x = 1.8 m is 9.0 m/s. (a) What is the velocity of the body at x = 4.1 m? (b) At what positive value of x will the body have a velocity of 2.5 m/s?
A particle of mass 8.0 kg moves along the horizontal x-axis. In the x direction the only force acting on it is the force F shown in the graph below. The particle starts from rest at x=0. The values indicated in the graph are:F1=4.1N;x1=1.0 m;x2=3.3 m;x3=5.7 m; What is the velocity of the particle at position x2? Give your answer to two significant figures. a)1,4 m/s b)3,4 m/s c)1,7 m/s d)27 m/s e)14 m/s f)0,68 m/s g)20 m/s h)10 m/s
A parachutist whose mass is 70 kg drops from a helicopter hovering 2500 m above the ground and falls toward the ground under the influence of gravity. Assume that the force due to air resistance is proportional to the velocity of the parachutist, with the proportionality constant b₁ = 30 N-sec/m when the chute is closed and b₂ = 90 N-sec/m when the chute is open. If the chute does not open until the velocity of the parachutist reaches 15 m/sec, after how many seconds will the parachutist reach the ground? Assume that the acceleration due to gravity is 9.81 m/sec². - The parachutist will reach the ground after (Round to two decimal places as needed.) * seconds.
An airplane starts from rest on the runway. The engines exert a constant force of 78.0 kN on the body of the plane (mass 9.20 × 104 kg) during takeoff. How far down the runway does the plane reach its takeoff speed of 64.6 m/s?
The only force acting on a 4.2 kg body as it moves along the positive x axis has an x component Fx= -4x N, where x is in meters. The velocity of the body at x = 1.7 m is 8.1 m/s. (a) What is the velocity of the body at x = 3.9 m? (b) At what positive value of x will the body have a velocity of 2.3 m/s? (a) Number i Units (b) Number i Units
The only force acting on a 1.7 kg body as it moves along the positive x axis has an x component Fx = -4x N, where x is in meters. The velocity of the body at x = 2.0 m is 11 m/s. (a) What is the velocity of the body at x = 3.7 m? (b) At what positive value of x will the body have a velocity of 2.2 m/s? (a) Number 9.91 (b) Number i 7.75 Units Units m/s m
Your answer is partially correct. The only force acting on a 4.5 kg body as it moves along the positive x axis has an x component F,= -4x N, where x is in meters. The velocity of the body at x = 1.4 m is 10 m/s. (a) What is the velocity of the body at x = 3.2 m? (b) At what positive value of x will the body have a velocity of 2.0 m/s? (a) Number 9.62 (b) Number 1.94 eTextbook and Media Units Units m/s m
An object has a mass of 15.3 kg and it has an initial velocity of 31.3 m/s (South) when it is acted upon by a force. The object's final velocity after the force has acted for a period of 5.20 s is 14.7 m/s (South). What is the force that acted on the object?
Consider the force diagram below applied to the particle of mass m=2 [kg] from time t = 0 to t = 7 [sec]. Assume x(0) = 2 [m] anx x(15) = 72 (m]. Find T. F(t) [N] F(t) 12 T 7. There is no correct answer OT= 4 sec OT = 6 sec OT = 5 sec OT = 3 sec
A bucket of water with a mass of 5 kg is accelerated upward by cord of negligible mass having a breaking strength of 75 N. If the bucket has an initial velocity of 2 m/s, how far will the bucket be raised in 5 s?
(Assume no friction forces) A train of 100 railroad cars each with a mass of 6 x 104 kg is being pulled by a locomotive that has a mass of 4.5 x 105 kg. The train leaves the freight yard at 12:00 noon on May the 5th. It starts from an initial velocity of 0. It takes the locomotive 8 kilometers to get the train up to a speed of 75 km/hr. The train then travels at an average speed of 75 km/hr for 4,200 km. After 4,200 km the train decelerates to a stop in 20 minutes. How long in minutes (to the nearest hundredth of a minute) did it take to reach 75 km/hr at the beginning? How much work was done to get the train to 75 km/hr. What was the KE of the train when it reached 75 km/hr? How much work was done on the train during the time it traveled the 4,200 km at 75 km/hr? What is the total distance the train traveled from beginning to end to the nearest km? What date and time does it arrive at its destination? (Date: Hour: min)? What is the work required to stop the train? What was…
A 20-kg particle moves with this trajectory: r ( t ) = − 40 t ȷ ^ + 25 t ı ^ + ( 5 ı ^ − 8 ȷ ^ ) e − 5 t Calculate the force on the particle. (Units are meters, seconds, and Newtons.)