= (5.90 N )î + (5.40 N )ŷ + (6.40 N )k acts on a 1.20 kg mobile object that moves from an initial position of á ; = (4.20 m î + (2.10 m )ĵ + (7.40 m )k to a final position of á f = (5.90 m )î + (8.20 m )ĵ + (5.50 m )k in 5.70s. Find (a) the work done on the object by the force in the 5.70 s interval, (b) the average power due to the force during that interval, and A force %3D f (c) the angle between vectors d ; and d f. i (a) Number i Units (b) Number i Units (c) Number i Units

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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A force \(\vec{F} = (5.90 \, \text{N}) \hat{\imath} + (5.40 \, \text{N}) \hat{\jmath} + (6.40 \, \text{N}) \hat{k}\) acts on a 1.20 kg mobile object that moves from an initial position of \(\vec{d}_i = (4.20 \, \text{m}) \hat{\imath} + (2.10 \, \text{m}) \hat{\jmath} + (7.40 \, \text{m}) \hat{k}\) to a final position of \(\vec{d}_f = (5.90 \, \text{m}) \hat{\imath} + (8.20 \, \text{m}) \hat{\jmath} + (5.50 \, \text{m}) \hat{k}\) in 5.70 s. Find (a) the work done on the object by the force in the 5.70 s interval, (b) the average power due to the force during that interval, and (c) the angle between vectors \(\vec{d}_i\) and \(\vec{d}_f\).

- (a) Calculate the work done:  
  Number: [Input field]  
  Units: [Dropdown menu]

- (b) Calculate the average power:  
  Number: [Input field]  
  Units: [Dropdown menu]

- (c) Calculate the angle between the vectors:  
  Number: [Input field]  
  Units: [Dropdown menu]
Transcribed Image Text:A force \(\vec{F} = (5.90 \, \text{N}) \hat{\imath} + (5.40 \, \text{N}) \hat{\jmath} + (6.40 \, \text{N}) \hat{k}\) acts on a 1.20 kg mobile object that moves from an initial position of \(\vec{d}_i = (4.20 \, \text{m}) \hat{\imath} + (2.10 \, \text{m}) \hat{\jmath} + (7.40 \, \text{m}) \hat{k}\) to a final position of \(\vec{d}_f = (5.90 \, \text{m}) \hat{\imath} + (8.20 \, \text{m}) \hat{\jmath} + (5.50 \, \text{m}) \hat{k}\) in 5.70 s. Find (a) the work done on the object by the force in the 5.70 s interval, (b) the average power due to the force during that interval, and (c) the angle between vectors \(\vec{d}_i\) and \(\vec{d}_f\). - (a) Calculate the work done: Number: [Input field] Units: [Dropdown menu] - (b) Calculate the average power: Number: [Input field] Units: [Dropdown menu] - (c) Calculate the angle between the vectors: Number: [Input field] Units: [Dropdown menu]
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