Five moles of gas initially at a pressure of 2.00 atm and a volume of 0.300 L has internal energy equal to 91.0 J. In its final state, the gas is at a pressure of 1.50 atm and a volume of 0.800 L, and its internal energy equals 182 J.Three paths are plotted on a PV diagram, which has a horizontal axis labeled V (liters), and a vertical axis labeled P (atm).The green path starts at point I (0.300,2.00), extends vertically down to point A(0.300,1.50), then extends horizontally to point F (0.800,1.50).The blue path starts at point I (0.300,2.00), and extends down and to the right to end at point F (0.800,1.50).The orange path starts at point I (0.300,2.00), extends horizontally to the right to point B (0.800,2.00), then extends vertically down to end at point F (0.800,1.50).(a) For the paths IAF, IBF, and IF in the figure above, calculate the work done on the gas.WIAF=JWIBF=JWIF=J(b) For the paths IAF, IBF, and IF in the figure above, calculate the net energy transferred to the gas by heat in the process.QIAF=JQIBF=JQIF=J P (atm)2.00B1.50FV (liters)0.3000.800

a) i) For the process IAF, the gas’s work done can be represented as, The process IA is an…

Answered: (a) For the paths IAF, IBF, and IF in…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Related questions

Question

100%

Five moles of gas initially at a pressure of 2.00 atm and a volume of 0.300 L has internal energy equal to 91.0 J. In its final state, the gas is at a pressure of 1.50 atm and a volume of 0.800 L, and its internal energy equals 182 J.

Three paths are plotted on a PV diagram, which has a horizontal axis labeled V (liters), and a vertical axis labeled P (atm).

The green path starts at point I (0.300,2.00), extends vertically down to point A(0.300,1.50), then extends horizontally to point F (0.800,1.50).
The blue path starts at point I (0.300,2.00), and extends down and to the right to end at point F (0.800,1.50).
The orange path starts at point I (0.300,2.00), extends horizontally to the right to point B (0.800,2.00), then extends vertically down to end at point F (0.800,1.50).

(a) For the paths IAF, IBF, and IF in the figure above, calculate the work done on the gas.

W_IAF	=	J
W_IBF	=	J
W_IF	=	J

(b) For the paths IAF, IBF, and IF in the figure above, calculate the net energy transferred to the gas by heat in the process.

Q_IAF	=	J
Q_IBF	=	J
Q_IF	=	J

P (atm)
2.00
B
1.50
F
V (liters)
0.300
0.800

Expert Solution

Trending now

This is a popular solution!

Step by step

Solved in 2 steps with 16 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions