A food product containing 80% moisture content is being frozen. Estimate the specific heat of the product at -6 ° C when 80% of the water is frozen. The specific heat of the dry product is 2 kJ / (kg ° C). it is assumed that the specific heat of water at -10 ° C is the same as the specific heat of water at 0 ° C, and the specific heat of ice follows the function Cp ice = 0.0062 Freezing point + 2.0649. Cp of frozen product = .... kJ / kg ° C.

A food product containing 80% moisture content is being frozen. Estimate the specific heat of the product at -6 ° C when 80% of the water is frozen. The specific heat of the dry product is 2 kJ / (kg ° C). it is assumed that the specific heat of water at -10 ° C is the same as the specific heat of water at 0 ° C, and the specific heat of ice follows the function Cp ice = 0.0062 Freezing point + 2.0649. Cp of frozen product = .... kJ / kg ° C.

Similar questions

FOLLOWING CONSTANTS ARE GIVEN FOR CALCULATIONS. Specific Heat of Water = 4186 J/kg °C, Specific Heat of Iron = 452 J /kg °C, Specific Heat of Ice = 2093 J/kg °C, Specific Heat of Lead = 130 J/kg °C Latent Heat of Fusion = 3.34 x 105 J/kg, Specific Heat of Copper = 385.1J /kg.'C Density of iron = 7.874 g /cm3 Density of copper = 8.95 g /cm3 3. 5 kg of ice at 0 °C is mixed with 1.5 kg of steam at 100 °C. Calculate the final temperature of the mixture.
1. Thermography is a technique for measuring radiant heat and detecting variations in surface temperatures that may be medically, environmentally, or militarily meaningful. (a) What is the percent increase in the rate of heat transfer by radiation from a given area at a temperature of 34.3 deg C compared with that at 33.5 deg C, such as on a person's skin? % Increase = % (b) What is the percent increase in the rate of heat transfer by radiation from a given area at a temperature of 34 deg C compared with that at 20.3 deg C, such as for warm and cool automobile hoods? % Increase= %
1.2-kg of ice at -6.0°C is dropped into 5.0 L (5.566-kg) of car coolant. The initial temperature of the coolant is 25.0°C. The ice and coolant are insulated, so energy transfers to the outside is negligible. After hours, all ice melts and the final temperature of the mixture of water-coolant is 1.8°C. The specific heat of ice is 2090 J/kg °C; the specific heat of water is 4186 J/kg °C; the latent heat of fusion for water is 334000 J/kg. A. What is the energy needed for heating the ice to 0 °C? B. Determine the energy needed to melt the ice into water. C. Determine the total energy needed to heat the -6.0°C ice to 1.8°C water. (Please note: the total energy also includes the part heating water from 0.0 °C to 1.8 °C.) D. Determine the specific heat capacity of the coolant.
For item 42: Table D2 Determination of Specific Heat of a Metal Initial mass of metal, mm (g) Initial temperature of metal, Tm,0 (°C) Initial mass of water, mw (g) Initial temperature ofwater, Tw,0 (°C) Final Temperature of mixture, T,(°C) Experimental Specific Heat cal of metal Cexp Actual Specific Heat of cal metal Cact g.Cº. Percentage Error Copper 30 42.) 110 43.) 125 20 21.94 0.9195 % For Item 42: choices for number 42 0.9180 0.9436 0.9513 0.8154 0.8354 For item 43: choices for number 43 0.17 O 0.16 0.15 0.18 0.19
1. (a) The number of kilocalories in food is determined by calorimetry techniques in which the food is burned and the amount of heat transfer is measured. How many kilocalories per gram are there in a 6-g peanut if the energy from burning it is transferred to 0.5 kg of water held in a 0.1 -kg aluminum cup, causing a 55.9 °C temperature increase? The specific heat of water is 1.00 kcal/kg °C, and the specific heat of aluminum cup is 0.215 kcal/kg °C. Q kcal/g mp (b) Compare your answer to labeling information found on a package of peanuts and comment on whether the values are consistent. A label for unsalted dry roasted peanuts says that 30 g contains 185 calories (kcal). Find the (Q/m) from calorimetry techniques of the label on a box of roasted peanuts. Q EGE 4.86 m cal m label
The temperature of a 63 g sample of an unknown substance is raised from 28° C to 86° C when 390 calories of heat are added . What is the specific heat of the sample , in cal/g . C ? Enter your calculated value to the nearest .001 cal/g . C .
Radioactive decay of elements in the earth’s interior results in a mean heat flux through the Earth’s surfaceof 5×10−2Wm−2. What is the flux expressed as a fraction of the energy flux due to thermal re-radiation of absorbed solar energy? If radioactive decay were the only heat source for the Earth, what would the Earth’s temperature be?