1.0 kg ice from a freezer

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### Heat Exchange in Ice-Water Mixture

**Problem Statement:**

1.0 kg of ice from a freezer at -20 °C is added to a reservoir containing 2.0 kg of water at 80 °C. Assuming no heat loss to the surroundings, the mixture reaches thermal equilibrium. Given the specific heat capacities:
- Specific heat of water: 4186 J/(kg·K)
- Specific heat of ice: 2090 J/(kg·K)
- Latent heat of fusion for ice: 3.35 x 10^5 J/kg 

We are required to solve for the following:
a) How much heat is required to increase the temperature of the ice to 0 °C?
b) How much heat is required to melt the ice to water at 0 °C?
c) What is the final temperature of the mixture?

### Solution:

#### a) Heat required to raise the temperature of ice from -20 °C to 0 °C:
The formula to calculate the heat (Q) required to change the temperature of a substance is:
\[ Q = m \cdot c \cdot \Delta T \]
Where \( m \) is the mass, \( c \) is the specific heat capacity, and \( \Delta T \) is the change in temperature.

For ice:
\[ m = 1.0 \, \text{kg} \]
\[ c = 2090 \, \text{J/(kg·K)} \]
\[ \Delta T = 0 \, °C - (-20 \, °C) = 20 \, °C \]

So,
\[ Q = 1.0 \, \text{kg} \times 2090 \, \text{J/(kg·K)} \times 20 \, \text{K} \]
\[ Q = 41800 \, \text{J} \]

#### b) Heat required to melt the ice to water at 0 °C:
The formula to calculate the heat (Q) required to melt a substance is:
\[ Q = m \cdot L_f \]
Where \( L_f \) is the latent heat of fusion.

For ice:
\[ m = 1.0 \, \text{kg} \]
\[ L_f = 3.35 \times 10^5 \, \text{J/kg} \]

So,
\[ Q
Transcribed Image Text:### Heat Exchange in Ice-Water Mixture **Problem Statement:** 1.0 kg of ice from a freezer at -20 °C is added to a reservoir containing 2.0 kg of water at 80 °C. Assuming no heat loss to the surroundings, the mixture reaches thermal equilibrium. Given the specific heat capacities: - Specific heat of water: 4186 J/(kg·K) - Specific heat of ice: 2090 J/(kg·K) - Latent heat of fusion for ice: 3.35 x 10^5 J/kg We are required to solve for the following: a) How much heat is required to increase the temperature of the ice to 0 °C? b) How much heat is required to melt the ice to water at 0 °C? c) What is the final temperature of the mixture? ### Solution: #### a) Heat required to raise the temperature of ice from -20 °C to 0 °C: The formula to calculate the heat (Q) required to change the temperature of a substance is: \[ Q = m \cdot c \cdot \Delta T \] Where \( m \) is the mass, \( c \) is the specific heat capacity, and \( \Delta T \) is the change in temperature. For ice: \[ m = 1.0 \, \text{kg} \] \[ c = 2090 \, \text{J/(kg·K)} \] \[ \Delta T = 0 \, °C - (-20 \, °C) = 20 \, °C \] So, \[ Q = 1.0 \, \text{kg} \times 2090 \, \text{J/(kg·K)} \times 20 \, \text{K} \] \[ Q = 41800 \, \text{J} \] #### b) Heat required to melt the ice to water at 0 °C: The formula to calculate the heat (Q) required to melt a substance is: \[ Q = m \cdot L_f \] Where \( L_f \) is the latent heat of fusion. For ice: \[ m = 1.0 \, \text{kg} \] \[ L_f = 3.35 \times 10^5 \, \text{J/kg} \] So, \[ Q
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