Expert solution/answer Specific heat of the water is 4.18 kJ/kg. °C. The expression for the heat transfer of the cold beverage is: Q = mc(T, -T) cold i cold 10 m (4.18 kJ/kg - °C)(48°C –16°C) 1 mL = (120 mL ) (10 J = (16.0×10* kJ) 1 kJ = 16 J I have used the expert formula above in calculating (d), and it happens to be section (c) answer is wrong but (d), is correct...may you please re-check for me where the problem is with expert's solution (c.) Solution (d) Q = MhotC (Tf – T;i hot) 16 J I have used the expert formula above in calculating (d), and it happens to be section (c) answer is wrong but (d), is correct...may you please re-check for me where the problem is with expert's solution (c.) Solution (d) Q = MhotC (Tf – Ti hot) [10-5m²- (120mL) (4. 18 kJ/kg.°C) (48-69°C) 1ml (103 ('10.5 x 10*kJ) () kJ = 10.5 Joules The formula above has worked for section (d)...I don't know why section c is not correct.
Energy transfer
The flow of energy from one region to another region is referred to as energy transfer. Since energy is quantitative; it must be transferred to a body or a material to work or to heat the system.
Molar Specific Heat
Heat capacity is the amount of heat energy absorbed or released by a chemical substance per the change in temperature of that substance. The change in heat is also called enthalpy. The SI unit of heat capacity is Joules per Kelvin, which is (J K-1)
Thermal Properties of Matter
Thermal energy is described as one of the form of heat energy which flows from one body of higher temperature to the other with the lower temperature when these two bodies are placed in contact to each other. Heat is described as the form of energy which is transferred between the two systems or in between the systems and their surrounding by the virtue of difference in temperature. Calorimetry is that branch of science which helps in measuring the changes which are taking place in the heat energy of a given body.
Initial temperature hot water 69° C,
Final temperature after adding cold water 48° C.
Initial temperature of cold water is 16° C
Quantity warm water 175 ml
c)What is your calculated
d) What is your calculated heat transfer (Q) of the hot beverage when 4 ounces (120 mL) of cold beverage was added? Report your answer in Joules.
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