1. (a) The number of kilocalories in food is determined by calorimetry techniques in which the food is burned and the amount of heat transfer is measured. How many kilocalories per gram are there in a 6-g peanut if the energy from burning it is transferred to 0.5 kg of water held in a 0.1 -kg aluminum cup, causing a 55.9 °C temperature increase? The specific heat of water is 1.00 kcal/kg °C, and the specific heat of aluminum cup is 0.215 kcal/kg °C. Q mp (b) Compare your answer to labeling information found on a package of peanuts and comment on whether the values are consistent. A label for unsalted dry roasted peanuts says that 30 g contains 185 calories (kcal). Find the (Q/m) from calorimetry techniques of the label on a box of roasted peanuts. 4.86 Q m cal Q kcal/g

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### Learning Objective: Determining Caloric Content in Food Using Calorimetry Techniques

#### Problem 1:
a) The number of kilocalories in food is determined by calorimetry techniques in which the food is burned and the amount of heat transfer is measured. How many kilocalories per gram are there in a 6 g peanut if the energy from burning it is transferred to 0.5 kg of water held in a 0.1 kg aluminum cup, causing a 55.9 °C temperature increase?

Given Data:
- Mass of water (\(m_{water}\)): 0.5 kg
- Mass of aluminum cup (\(m_{aluminum}\)): 0.1 kg
- Temperature increase (\(\Delta T\)): 55.9 °C
- Specific heat of water (\(c_{water}\)): 1.00 kcal/kg °C
- Specific heat of aluminum cup (\(c_{aluminum}\)): 0.215 kcal/kg °C

The heat absorbed by the water (\(Q_{water}\)) can be calculated using the formula:
\[ Q_{water} = m_{water} \times c_{water} \times \Delta T \]

The heat absorbed by the aluminum cup (\(Q_{aluminum}\)) can be calculated using the formula:
\[ Q_{aluminum} = m_{aluminum} \times c_{aluminum} \times \Delta T \]

The total heat (\(Q_{total}\)) is the sum of heat absorbed by the water and the aluminum cup:
\[ Q_{total} = Q_{water} + Q_{aluminum} \]

To find the kilocalories per gram of peanut (\( \frac{Q}{m_p} \)):
\[ \frac{Q}{m_p} = \frac{Q_{total}}{m_{peanut}} \]

Final Calculation:
\[ \frac{Q}{m_p} = \boxed{4.86 \, \text{kcal/g}} \] 

b) Compare your answer to labeling information found on a package of peanuts and comment on whether the values are consistent. A label for unsalted dry roasted peanuts says that 30 g contains 185 kilocalories (kcal).

Find the \( \left(\frac{Q}{m}\right) \) from calorimetry techniques of the label on a box of roasted peanuts:
\[ \frac{Q}{
Transcribed Image Text:### Learning Objective: Determining Caloric Content in Food Using Calorimetry Techniques #### Problem 1: a) The number of kilocalories in food is determined by calorimetry techniques in which the food is burned and the amount of heat transfer is measured. How many kilocalories per gram are there in a 6 g peanut if the energy from burning it is transferred to 0.5 kg of water held in a 0.1 kg aluminum cup, causing a 55.9 °C temperature increase? Given Data: - Mass of water (\(m_{water}\)): 0.5 kg - Mass of aluminum cup (\(m_{aluminum}\)): 0.1 kg - Temperature increase (\(\Delta T\)): 55.9 °C - Specific heat of water (\(c_{water}\)): 1.00 kcal/kg °C - Specific heat of aluminum cup (\(c_{aluminum}\)): 0.215 kcal/kg °C The heat absorbed by the water (\(Q_{water}\)) can be calculated using the formula: \[ Q_{water} = m_{water} \times c_{water} \times \Delta T \] The heat absorbed by the aluminum cup (\(Q_{aluminum}\)) can be calculated using the formula: \[ Q_{aluminum} = m_{aluminum} \times c_{aluminum} \times \Delta T \] The total heat (\(Q_{total}\)) is the sum of heat absorbed by the water and the aluminum cup: \[ Q_{total} = Q_{water} + Q_{aluminum} \] To find the kilocalories per gram of peanut (\( \frac{Q}{m_p} \)): \[ \frac{Q}{m_p} = \frac{Q_{total}}{m_{peanut}} \] Final Calculation: \[ \frac{Q}{m_p} = \boxed{4.86 \, \text{kcal/g}} \] b) Compare your answer to labeling information found on a package of peanuts and comment on whether the values are consistent. A label for unsalted dry roasted peanuts says that 30 g contains 185 kilocalories (kcal). Find the \( \left(\frac{Q}{m}\right) \) from calorimetry techniques of the label on a box of roasted peanuts: \[ \frac{Q}{
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