a- fo Ax. A a. 4. (5) For the member loaded as shown, with the smooth collar at A and roller support at B: Draw a complete Free Body Diagram (FBD) for the rigid body. b. Determine the support reactions necessary for equilibrium of the member. AY ма Ax 1 ≤ Fy=6 1 O 900 N : 500 N.m b- 2 Fx = 0 (52M₁) = 0 Ay (3) - 500 N. m² = 0 ΕΣΜΑ oups ok but Ay = 1 500 N.m 3 [AY = 267N 1) - 1/2 Ay - 900-By By cos 45° BY = 900 N -1.5 m A H 500 Nm By By = -1/2 BY TBY pe mie di go forgot moment from 900N, and -1.5 m Ay - 900 Ay - 900 cos450 -10 37 N 1037 N TOM 45° еву through Ay goes point A. 17 Of acts only in y-directin 24 cos 45º = 0 -Y₂ 1 m pairs) N Ax = 0 Ay = 16+NA Ov WASTNIN

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
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Correct this assignment and write a sentence or two explaining why I made the mistake
a-
A
fo
Ax.
Fall 2023
4. (5) For the member loaded as shown, with the smooth collar at A and roller support at B:
Draw a complete Free Body Diagram (FBD) for the rigid body.
b. Determine the support reactions necessary for equilibrium of the member.
a.
12Fy-
ма
Ax = 0
=
b- 2 Fx = 0
(+5 ≤MA) = 0 Ay (3)
AY
900 N
:
500 N.m
=
A
=
1.5 m
-1/2
By
D
900 N
0
ok
oops
SOON. m² =
but
500 N.m
3
67N 17 -12
11
500 N·m
By
- 10:37 N
By = 1037 NU
-1.5 m
Ay - 900 - By cos 45º = 0
By cos 45º = Ay - 900
BY
Ay - 900
cos450
pë me di
brgot moment from
900N, and
TOM
l By-
h
Ay goes through
point A.
HE
45°
00,1
acts only in y-direction
- 12
pak
21 IN
1 m
B
ATT
sk
Ax = 0
Ay = 16+NA
By 4037 NV
Transcribed Image Text:a- A fo Ax. Fall 2023 4. (5) For the member loaded as shown, with the smooth collar at A and roller support at B: Draw a complete Free Body Diagram (FBD) for the rigid body. b. Determine the support reactions necessary for equilibrium of the member. a. 12Fy- ма Ax = 0 = b- 2 Fx = 0 (+5 ≤MA) = 0 Ay (3) AY 900 N : 500 N.m = A = 1.5 m -1/2 By D 900 N 0 ok oops SOON. m² = but 500 N.m 3 67N 17 -12 11 500 N·m By - 10:37 N By = 1037 NU -1.5 m Ay - 900 - By cos 45º = 0 By cos 45º = Ay - 900 BY Ay - 900 cos450 pë me di brgot moment from 900N, and TOM l By- h Ay goes through point A. HE 45° 00,1 acts only in y-direction - 12 pak 21 IN 1 m B ATT sk Ax = 0 Ay = 16+NA By 4037 NV
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