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A five stories building was subjected to factored gravity loads and factored wind shears as shown below. Each floor has 40,000 square foot of area and is subjected to factored gravity load Wu = 300 psf. Floor Height Vus + Ft Kips in F'c psi 5 12 100 0.3 6000 4 12 200 0.25 6000 3 12 300 0.2 8000 2 18 400 0.14 8000 Vus is the story wind load shear and + is the story lateral drift due to the wind load. For the fifth floor column, the column is 18"x18" and is subjected to the following: Pu= 600 kips, M1u_gravity = Mu2_gravity = 20 k-ft, M1u_wind = Mu2_wind= 75 k-ft For the second floor column, the column is 28"x28" and is subjected to the following: Pu= 2400 kips, M₁u_gravity = Mu2_gravity = 40 k-ft, M₁u_wind = Mu2_wind= 300 k-ft For each of the fifth and second floor, determine: a) Whether the columns are slender or short columns b) Determine the design moments and axial loads Assume that K=1.0 for non-sway frames and k=1.2 for sway frames. Neglect the difference between the clear height of columns and the floor height. All columns are in single curvature.

A five stories building was subjected to factored gravity loads and factored wind shears as shown below. Each floor has 40,000 square foot of area and is subjected to factored gravity load Wu = 300 psf. Floor Height Vus + Ft Kips in F'c psi 5 12 100 0.3 6000 4 12 200 0.25 6000 3 12 300 0.2 8000 2 18 400 0.14 8000 Vus is the story wind load shear and + is the story lateral drift due to the wind load. For the fifth floor column, the column is 18"x18" and is subjected to the following: Pu= 600 kips, M1u_gravity = Mu2_gravity = 20 k-ft, M1u_wind = Mu2_wind= 75 k-ft For the second floor column, the column is 28"x28" and is subjected to the following: Pu= 2400 kips, M₁u_gravity = Mu2_gravity = 40 k-ft, M₁u_wind = Mu2_wind= 300 k-ft For each of the fifth and second floor, determine: a) Whether the columns are slender or short columns b) Determine the design moments and axial loads Assume that K=1.0 for non-sway frames and k=1.2 for sway frames. Neglect the difference between the clear height of columns and the floor height. All columns are in single curvature.

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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A five stories building was subjected to factored gravity loads and factored wind shears as shown below. Each floor has 40,000 square foot of area and is subjected to factored gravity load Wu = 300 psf. Floor Height Vus + Ft Kips in F'c psi 5 12 100 0.3 6000 4 12 200 0.25 6000 3 12 300 0.2 8000 2 18 400 0.14 8000 Vus is the story wind load shear and + is the story lateral drift due to the wind load. For the fifth floor column, the column is 18"x18" and is subjected to the following: Pu= 600 kips, M1u_gravity = Mu2_gravity = 20 k-ft, M1u_wind = Mu2_wind= 75 k-ft For the second floor column, the column is 28"x28" and is subjected to the following: Pu= 2400 kips, M₁u_gravity = Mu2_gravity = 40 k-ft, M₁u_wind = Mu2_wind= 300 k-ft For each of the fifth and second floor, determine: a) Whether the columns are slender or short columns b) Determine the design moments and axial loads Assume that K=1.0 for non-sway frames and k=1.2 for sway frames. Neglect the difference between the clear height of columns and the floor height. All columns are in single curvature.
Transcribed Image Text:A five stories building was subjected to factored gravity loads and factored wind shears as shown below. Each floor has 40,000 square foot of area and is subjected to factored gravity load Wu = 300 psf. Floor Height Vus + Ft Kips in F'c psi 5 12 100 0.3 6000 4 12 200 0.25 6000 3 12 300 0.2 8000 2 18 400 0.14 8000 Vus is the story wind load shear and + is the story lateral drift due to the wind load. For the fifth floor column, the column is 18"x18" and is subjected to the following: Pu= 600 kips, M1u_gravity = Mu2_gravity = 20 k-ft, M1u_wind = Mu2_wind= 75 k-ft For the second floor column, the column is 28"x28" and is subjected to the following: Pu= 2400 kips, M₁u_gravity = Mu2_gravity = 40 k-ft, M₁u_wind = Mu2_wind= 300 k-ft For each of the fifth and second floor, determine: a) Whether the columns are slender or short columns b) Determine the design moments and axial loads Assume that K=1.0 for non-sway frames and k=1.2 for sway frames. Neglect the difference between the clear height of columns and the floor height. All columns are in single curvature.
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