E = 22.324 x 10° psi beol = 1.00 in. deol = 0.066 in. Weight of each floor 4.13 lb 6.000 Column 1.000| 0.066

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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000
Level 3
E = 22.324 x 10° psi
15 000
beol = 1.00 in.
deol = 0.066 in.
Level 2
Weight of each floor 4.13 lb
15 000
6.000
Column
1.000 |
Level 1
0.066
Shaking
ELEVATION
PLAN
The model building you will be analyzing is shown above. Relevant properties and the shaking direction
are also given above. Assume that the height of each story is 16 in.
a) Use the generalized coordinate method and calculate the fundamental frequency (first natural
frequency) of vibration for this building.
Transcribed Image Text:000 Level 3 E = 22.324 x 10° psi 15 000 beol = 1.00 in. deol = 0.066 in. Level 2 Weight of each floor 4.13 lb 15 000 6.000 Column 1.000 | Level 1 0.066 Shaking ELEVATION PLAN The model building you will be analyzing is shown above. Relevant properties and the shaking direction are also given above. Assume that the height of each story is 16 in. a) Use the generalized coordinate method and calculate the fundamental frequency (first natural frequency) of vibration for this building.
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