6.DETAILS(a) What are the components of the acceleration of the fish?a =m/s²m/s²A fish swimming in a horizontal plane has velocity = (4.00 i + 1.00 j) m/s at a point in the ocean where the position relative to a certain rock is r = (16.01 - 1.20 j) m.After the fish swims with constant acceleration for 15.0 s, its velocity is = (25.0 16.00 j) m/s.(b) What is the direction of its acceleration with respect to unit vector î?counterclockwise from the +x-axis(c) If the fish maintains constant acceleration, where is it at t = 26.0 s?X =y =mmIn what direction is it moving?MY NOTEScounterclockwise from the +x-axis.ASK YOUR TEACHER

Name: 6.DETAILS(a) What are the components of the acceleration of the fish?
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Description: 6.DETAILS(a) What are the components of the acceleration of the fish?a =m/s²m/s²A fish swimming in a horizontal plane has velocity = (4.00 i + 1.00 j) m/s at a point in the ocean where the position relative to a certain rock is r = (16.01 - 1.20 j)

Given data, The initial velocity vector of the fishvi⇀=4i^+j^ m/s The final velocity vector of the…

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A fish swimming in a horizontal plane has velocity = (4.00 i + 1.00 j) m/s at a point in the ocean where the position relative to a certain rock is r- (16.01-1.20 j) m. After the fish swims with constant acceleration for 15.0 s, its velocity is = (25.0 16.00 j) m/s. (a) What are the components of the acceleration of the fish? ax= m/s2 ay = m/s² (b) What is the direction of its acceleration with respect to unit vector i? counterclockwise from the +x-axis (c) If the fish maintains constant acceleration, where is it at t= 26.0 s? X= y= m m

A fish swimming in a horizontal plane has velocity = (4.00 i + 1.00 j) m/s at a point in the ocean where the position relative to a certain rock is r- (16.01-1.20 j) m. After the fish swims with constant acceleration for 15.0 s, its velocity is = (25.0 16.00 j) m/s. (a) What are the components of the acceleration of the fish? ax= m/s2 ay = m/s² (b) What is the direction of its acceleration with respect to unit vector i? counterclockwise from the +x-axis (c) If the fish maintains constant acceleration, where is it at t= 26.0 s? X= y= m m

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6.
DETAILS
(a) What are the components of the acceleration of the fish?
a =
m/s²
m/s²
A fish swimming in a horizontal plane has velocity = (4.00 i + 1.00 j) m/s at a point in the ocean where the position relative to a certain rock is r = (16.01 - 1.20 j) m.
After the fish swims with constant acceleration for 15.0 s, its velocity is = (25.0 16.00 j) m/s.
(b) What is the direction of its acceleration with respect to unit vector î?
counterclockwise from the +x-axis
(c) If the fish maintains constant acceleration, where is it at t = 26.0 s?
X =
y =
m
m
In what direction is it moving?
MY NOTES
counterclockwise from the +x-axis.
ASK YOUR TEACHER

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