An object moves with its position obeying x = 5t 3. 6t 2 and y = 3t 1 + 4t 4. The magnitude of its acceleration att = 1s is 57 m/s 2 34 m/s 2 26 m/s 2 44 m/s 2
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A: Given: Position of the particle, x = 24t - 2t3 , where time (t) is mesured in second (s) and…
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A: GivenPosition is given byx=(22t-1t3)m t is in second
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A: Given, The initial speed of the speedboat, v1x = 8.81 msv1 = -2.45 ms Time, t = 6.63 s…
Q: A particle starts from the origin at t = 0 with a velocity of 7.8 and moves in the xy plane with a…
A: Solution:-Given thatInitial velocity (u→)=(7.8 j^) m/sacceleration (a→)=(4.4 i^+3 j^) m/s2x…
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Q: 1. A particle initially located at the origin has a constant acceleration of a = 3.00j m/s and an…
A: Given data The magnitude of the constant acceleration is a = 3 j m/s2 The initial velocity of the…
Q: The vector position of a particle varies in time according to the expression: r =( 20ti+(2 + 20t-5t…
A: The position vector of the particle is given as: r→=20t i^+2+20t-5t2j^ It is required to find its…
Q: The position of a particle is 7(t) = (2.0t21-3.0t Jm.What is the magnitude of the acceleration (in…
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Q: The x-coordinate of a particle in curvilinear motion is given by x = 2.4t3 - 4.3t where x is in feet…
A: Given:- The x coordinate of a particle in curvilinear motion is given by x= 2.4t3-4.3t where x is…
Q: In the position formula, x(t) = 2Q t^2 - 4Ht + K what is the value of the acceleration?
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Q: The position of a particle moving along the x-axis is given by s(t)=(5.8 m) -(3.06 m/s)t. What ist…
A: Given data: Position of particle s(t)=(5.8 m) -(3.06 m/s)t Required: The displacement of the…
Q: A particle moving along the x-axis has its position described by the function x =( 5.00 t^3-5.00t+t+…
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Q: A computer model displays the motion of a particle on a coordinate system in real time. At time t =…
A: Velocity components: In x-direction, v = 0 In y-direction, v = 6.8 m/s Acceleration components: In…
Q: The figure(Figure 1) shows the velocity graph of a particle moving along the x-axis. Its initial…
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57 m/s
34 m/s 2
26 m/s 2
44 m/s 2"
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- A car drives around a circular track of diameter 156 m at a constant speed of 33.0 m/s. During the time it takes the car to travel 102 degrees around, what is the magnitude of the car s average acceleration? 13.96 m/s^2 6.98 m/s^2 12.19 m/s^2 0 m/s^2 CANNOT USE CENTRIPITAL MOTION EQUATION, must calculate average accelerationQuestion 2: The acceleration function of an object doing {(-0.2t)i+4j+1.5k} m/s?, where t is in s. If its initial velocity vo = 8i m/s, and initial position is at the origin, determine the magnitude of its position curvilinear motion is a = when t = 3 s. (а) 25.7 m (b) 38.9 m (c) 62.3 m (d) 22.1 mAt t1 = 3.00 s, the acceleration of a particle moving at constant speed in counterclockwise circular motion is an = (3.00 m/s?)ì + (6.00 m/s) ^ At t2 = 7.00 s (less than one period later), the acceleration is a2 = (6.00 m/s3)ì - (3.00 m/s2)î The period is more than 4.00 s. What is the radius of the circle?
- A particle moves along the x-axis according to the equation x = 2.00 +3.00t -1.00t^2, where x is in meters and t is in seconds. At t = 3.00s , find the acceleration of the particle.I need part d and eThe x-coordinate of a particle in curvilinear motion is given by x= 2.1t³ -2.4t where x is in feet and t is in seconds. The y-component of acceleration in feet per second squared is given by ay = 2.0t. If the particle has y-components y = 0 and vy= 2.2 ft/sec when t = 0, find the magnitudes of the velocity v and acceleration a when t = 2.7 sec. Sketch the path for the first 2.7 seconds of motion, and show the velocity and acceleration vectors for t = 2.7 sec. Answers: V = i a= i ft/sec ft/sec²
- Number An ion's position vector is initially 7 = (2.4 m )î + (−7.4 m )3 + (6.5 m ). In unit-vector notation, what is its average velocity during the 6.7 s? )ĵ i 1 + = 9.1 m )i + (−9.9 m )ĵ + (−10 m )k, ) + (-10 m ), and 6.7 s later it is -0.37313433 Ĵ + MI -2.46268657 k Units m/sA particle has a position in space given by r = 2t^3 i + 4t^2 j - 3t k where r is in m and t in seconds. Find the magnitude of the instantaneous velocity at t = 3.0 s. 24 m/s 75 m/s 54 m/s 59 m/sPhysics A miniature quadcopter is located at x, = 2.25 m and y, =-2.70 m at t = 0 and moves with an average velocity having components Yav, x = 1.70 m/s and Yav, y =-2.50 m/s. What are the x- coordinate and y-coordinate (in m) of the quadcopter's position at t = 1.60 s? x-coordinate = y-coordinate = Please help! Thank you in advance!
- At t₁ = 3.00 s, the acceleration of a particle moving at constant speed in counterclockwise circular motion is a₁ = (3.00 m/s²)i + (6.00 m/s²)ĵ At t₂ = 7.00 s (less than one period later), the acceleration is a₂ (6.00 m/s²) - (3.00 m/s²) The period is more than 4.00 s. What is the radius of the circle?2. The velocity of a particle is given by v = {14t?î+ (4t + 3)j + 6t³k} m/s, where t is in seconds. If the particle is at the origin when t = 0, determine the magnitude of the particle's acceleration when t = 3 s. Also, what is the x, y, z coordinate position of the particle at this instant?A particle is constrained to travel along the path. If x = (4t*) m, wheret is in %3D seconds, determine the magnitude of the particle's acceleration in m/s when t = 0.5 s. = 4x %3D x = (4r*) m