A fish swimming in a horizontal plane has velocity V₁ = (4.00 î+ 1.00 j) m/s at a point in the ocean where the position relative to a certain rock is = (16.0 i 3.60 ĵ) m. After the fish swims with constant acceleration. for 15.0 s, its velocity is = (15.01 - 1.00 j) m/s. (a) What are the components of the acceleration of the fish? ay = m/s² m/s2 ay = (b) What is the direction of its acceleration with respect to unit vector i? counterclockwise from the +x-axis (c) If the fish maintains constant acceleration, where is it at t = 24.0 s? x = y = m m In what direction is it moving? counterclockwise from the +x-axis

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Chapter1: Units, Trigonometry. And Vectors
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A fish swimming in a horizontal plane has velocity V₁ = (4.00 i + 1.00 ĵ) m/s at a point in the ocean where the position relative to a certain rock is r = (16.01- 3.60 ĵ) m. After the fish swims with constant acceleration
for 15.0 s, its velocity is = (15.01 - 1.00 j) m/s.
(a) What are the components of the acceleration of the fish?
ax =
m/s2
m/s2
ay =
(b) What is the direction of its acceleration with respect to unit vector î?
counterclockwise from the +x-axis
(c) If the fish maintains constant acceleration, where is it at t = 24.0 s?
x =
y =
m
In what direction is it moving?
counterclockwise from the +x-axis
Transcribed Image Text:A fish swimming in a horizontal plane has velocity V₁ = (4.00 i + 1.00 ĵ) m/s at a point in the ocean where the position relative to a certain rock is r = (16.01- 3.60 ĵ) m. After the fish swims with constant acceleration for 15.0 s, its velocity is = (15.01 - 1.00 j) m/s. (a) What are the components of the acceleration of the fish? ax = m/s2 m/s2 ay = (b) What is the direction of its acceleration with respect to unit vector î? counterclockwise from the +x-axis (c) If the fish maintains constant acceleration, where is it at t = 24.0 s? x = y = m In what direction is it moving? counterclockwise from the +x-axis
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