An object moves in one dimensional motion with constant acceleration a = 4.5 m/s². At time t = 0 s, the object is at xo = 2.9 m and has an initial velocity of vo = 4 m/s. How far will the object move before it achieves a velocity of v = 7 m/s? Your answer should be accurate to the nearest 0.1 m.
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- The position of a particle moving along the x axis depends on the time according to the equation x = ct2 = bt3, where x is in meters and t in seconds.What are the units of (a) constant c and (b) constant b? Let their numerical values be 3.0 and 2.0, respectively. (c) At what time does the particle reach its maximum positive x position? From t = 0.0 s to t = 4.0 s, (d) what distance does the particle move and (e) what is its displacement? Find its velocity at times (f) 1.0 s, (g) 2.0 s, (h) 3.0 s, and (i) 4.0 s. Find its acceleration at times (j) 1.0 s, (k) 2.0 s, (l) 3.0 s, and (m) 4.0 s.A particle moves along the x-axis. The function x(t) gives the particle’s position at any time t ≥ 0: x(t) = t3-4t2+3t-2 a) What is the particle’s velocity v(t) at t=3s? b) What is the particle’s acceleration a(t) at t=3s? What is the direction of the particle’s motion at t=2s? at t=3s, is the particle’s speed increasing, decreasing, or neither?An object moves in along the x-axis with an acceleration given by: a = 9t (m/s2). The position of the object at t=0.0 is 5 m, and its velocity at t=0.0 s is 7 m/s. Calculate the position at t=8 s.
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