An object undergoes acceleration 2.3i +3.6j m/s² for 5.9 s at which time its velocity is 33i +15j m/s. What was the object's speed at the beginning of the 5.9 s interval?
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- The acceleration of an object (in m/s2) is given by the function a(t)=7sin(t)a(t)=7sin(t). The initial velocity of the object is v(0)=−1v(0)=-1 m/s. Round your answers to four decimal places. v(t) = -7cos(t) + 6 The objects displacement from time 0 to 3 is: 17.01216 meters Find the total distance traveled by the object from time 0 to time 3.answer in Three significant digitsAn object's position in the as a function of time obeys the equation; x(t) = 14.2/t2.17 + 5.1t3 where all constants have proper SI Units. What is the speed of the object in the x direction at t = 1.93 seconds?
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