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- What conclusion would be appropriate for an upper-tailed chi-squared test in each of the following situations? LUSE SALT (a) a=0.05, df = 4, x² = 11.25 O We would reject Ho O We would fail to reject Ho. (b) a = 0.01, df = 3, x² = 8.52 O We would reject Ho O We would fail to reject Ho (c) a = 0.10, df -2, x² - 4.06 = O We would reject Ho O We would fail to reject Ho (d) a = 0.01, k = 6, x² = 11.80 O We would reject Ho- O We would fail to reject Ho5Suppose you wish to test the hypothesis H0:P=0.9 versus H1:P≠0.9 based on a random sample of size 100 and number of successes 70. Find the value of the test statistic. (Note: use the continuity correction).
- Stoaches are fictional creatures, sometimes mistaken for mome raths. Suppose a two-tailed t-test is conducted to test for a difference between the population means of adult female stoach weights and adult male stoach weights. The female sample has 13 weights, and the male sample has 7 weights. The t-statistic for the test is -0.20542. What is the p-value? (Give your answer to 4 decimal places.) p-value:You are conducting a test of independence to see if getting the flu is independent of whether or not you got a flu shot. Use a = 0.05. Report all answers accurate to four decimal places. Here is the sample data. Category Got Flu Shot Did not get Flu Shot Category Got Flu Shot The expected observations for this table would be: Got the Flu Did not get Flu Shot The resulting (O - E)² E Got the Flu 18 51 Category Got Flu Shot Did not get Flu Shot Did not get the Flu 118 19 Got the Flu for finding the test are: Did not get the Flu What is the p-value for this test-statistic? P-Value = Did not get the Flu What is the chi-square test-statistic for this data? (add the results from the previous table) x² =You take a simple random sample of size 25 from a very large population in which the true proportioni p=0.1. Which statement below best describes what you know about the sampling distribution of p? (0.1)(0.9) (a) H,-0.1; o,- the distribution is skewed right. 25 (0.1)(0.9). 25 (b) H,=0.1; o,=. ; the distribution is skewed left. (0.1)(0.9). (c) ,=0.1; o,= the distribution is approximately Normal. %3D 25 (0.1)(0.9) (d) , the distribution is not approximately Normal. 25 =0.1; we cannot use the formula o, (0.1)(0.9) ; the distribution is approximately Normal. 25 (e) =0.1; we cannot use the formula o,
- What is the critical t score if you are testing a one-tailed hypothesis, α level of .05 with df = 36? a. 1.671 b. 2.026 c. 2.028 d. 1.697You are performing a left-tailed test with test statistic z=−2.04, find the p-value to 4 decimal places.Note: You will need to use the z and t sheet to get this answer.J Suppose that Shoe Sices Of American women have a bell Shaped elu standard with a mean of 8,37 and a eleviation of 1.49, using the empirical Rule what percentage of american women have Shoe Sizes that are no more than 9.su? do not Roundl your answer
- You take a simple random sample of size 25 from a very large population in which the true proportion is p = 0.1. Which statement below best describes what you know about the sampling distribution of p ? %3D Hp-hat 0.1; we cannot use the formula Op-hat = (0.1)(0.9) : the distribution is not approximately normal, 25 Hp-hat = 0.1; op-hat = (0.1)(0.9) : the distribution is skewed. 25 Hp-hat = 0.1; Op-hat = (0.10.9) ; the distribution is approximately normal. 25 Hn-hat = 0.1; we cannot use the formula op-hat = V (0.1)(0.9) 25 Op-hat ; the distribution is approximately normal. * Previous IMG 0218.jpeg Next Activa PAUSE PRT F12 F11 F10 F9 M3 PO UP F8 M2 HOME F7 M1 F6 INS F5 F4 M6 PO DN M4 DEL END10.You are conducting a multinomial hypothesis test for the claim that the 4 categories occur with the following frequencies:Ho : pA=0.2 pB=0.3; pC=0.1; pD=0.4Complete the table. Category ObservedFrequency ExpectedFrequency SquaredResidual A 38 B 41 C 10 D 57 What is the chi-square test-statistic for this data?χ2=Report all answers accurate to three decimal places.VERY IMPORTANT NOTE: Answers are reported to 3 decimal places, but you should use all the decimal places to calculate the final chi-square test statistic...DO NOT use the rounded number you report in the table.