What conclusion would be appropriate for an upper-tailed chi-squared test in each of the following situations?LUSE SALT(a) a=0.05, df = 4, x² = 11.25O We would reject HoO We would fail to reject Ho.(b) a = 0.01, df = 3, x² = 8.52O We would reject HoO We would fail to reject Ho(c) a = 0.10, df -2, x² - 4.06=O We would reject HoO We would fail to reject Ho(d) a = 0.01, k = 6, x² = 11.80O We would reject Ho-O We would fail to reject Ho

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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What conclusion would be appropriate for an upper-tailed chi-squared test in each of the following situations? In USE SALT (a) a = 0.05, df = 4, x² = 11.75 O we would reject Ho. O We would fail to reject Hg. (b) a = 0.01, df = 3, x? = 8.59 O We would reject Ho. O We would fail to reject Ho. (c) a = 0.10, df = 2, x2 = 4.46 O We would reject Ho. O We would fail to reject Hg. a = 0.01, k = 6, x? = 11.60 (d) O We would reject Ho. O We would fail to reject Ho.
You are conducting a test of homogeneity for the claim that two different populations have the same proportions of the following two characteristics. Here is the sample data. Category Population#1 Population#2 A 18 46 B 46 113 What is the chi-square test-statistic for this data?χ2= 0.023 is INCORRECTReport all answers accurate to three decimal places.
Note: For this problem, your answer should be rounded to two decimal places. In a particular municipality, it is believed that 25 percent of homes are not properly insulated. In order to test ?0:?=.25 vs. ??:?≠.25 (where ? is the population proportion of homes that are not properly insulated) a random sample of 300 homes was selected. In the sample, it was found that 108 homes were not properly insulated. If the null hypothesis is true, then the z-score for the sample proportion is:
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You are conducting a test of independence to see if getting the flu is independent of whether or not you got a flu shot. Use a = 0.05. Report all answers accurate to four decimal places. Here is the sample data. Category Got Flu Shot Did not get Flu Shot Category Got Flu Shot The expected observations for this table would be: Got the Flu Did not get Flu Shot The resulting (O - E)² E Got the Flu 18 51 Category Got Flu Shot Did not get Flu Shot Did not get the Flu 118 19 Got the Flu for finding the test are: Did not get the Flu What is the p-value for this test-statistic? P-Value = Did not get the Flu What is the chi-square test-statistic for this data? (add the results from the previous table) x² =
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You are conducting a test of independence for the daim that there is an association between morning beverage and age. Juice Coffee Pop Tea 5 32 | 43 less than 25 19 18 25 or older 27 30 2 What is the chi-square test-statistic and the corresponding p-value for this data? [three decimal accuracy] p-value = [three decimal accuracy]
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You are conducting a test of homogeneity for the claim that two different populations have the same proportions of the following two characteristics. Here is the sample data. Category Population#1 Population#2 A 34 100 B 46 15 What is the chi-square test-statistic for this data?χ2=Report all answers accurate to three decimal places.
The mean and the variance of a sample of size 16 from normal population are 32 and 8, respectively. For testing the hypotheses H,:0%=46vsH, : 0> # 4.6 thetest statistic is: Select one: O a.22.83 O b.19.57 () ¢.29.35 O d.26.09

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