(a) Find P(male linternal medicine). Round your answer to three decimal places. P(malelinternal medicine) = 1 Correct Answer: P (male internal medicine) = 0.682 Part 2 of 4 (b) Find P(psychiatry female). Round your answer to three decimal places. P(psychiatry female) = 1 %3D Correct Answer: P (psychiatry female) = 0.2 Part 3 of 4 (c) Are the characteristics "female" and "psychiatry" independent? Yes Correct Answer: Are the characteristics "female" and "psychiatry" independent? No

(a) Find P(male linternal medicine). Round your answer to three decimal places. P(malelinternal medicine) = 1 Correct Answer: P (male internal medicine) = 0.682 Part 2 of 4 (b) Find P(psychiatry female). Round your answer to three decimal places. P(psychiatry female) = 1 %3D Correct Answer: P (psychiatry female) = 0.2 Part 3 of 4 (c) Are the characteristics "female" and "psychiatry" independent? Yes Correct Answer: Are the characteristics "female" and "psychiatry" independent? No

Name: Doctor Specialties Below are listed the numbers of doctors in various
Uploaded: 2024-03-20T07:06:27.000Z
Channel: Bartleby
Description: Doctor Specialties Below are listed the numbers of doctors in various specialties by gender.Internal MedicinePsychiatryPathologyMale106,16427,31912,551Female49,54114,0666620Send data to ExcelChoose 1 doctor at random.Part 1 of 4(a) Find P (male lint

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Part B: Identify the test statistic___ (Round your answer to two decimals as needed.) Part C: Identify the P-value___ (Round your answer to three decimals as needed.)
What percent of females don't have heart disease? Sex (1=Male 2=Female) 1 2 Total Ever told heart disease (1=Yes 2=No) 1 Count 73 96 169 % within Ever told heart 43.2% 56.8% 100.0% disease (1=Yes 2=No) % within Sex (1=Male 10.2% 9.3% 9.7% 2=Female) % of Total 4.2% 5.5% 9.7% 2 Count 640 941 1581 % within Ever told heart 40.5% 59.5% 100.0% disease (1=Yes 2=No) % within Sex (1=Male 2=Female) 89.8% 90.7% 90.3% % of Total 36.6% 53.8% 90.3% Total Count 713 1037 1750 % within Ever told heart disease (1=Yes 2=No) 40.7% 59.3% 100.0% % within Sex (1=Male 100.0% 100.0% 100.0% 2=Female) % of Total 40.7% 59.3% 100.0% 59.5% 89.8% 53.8% 90.7%
(a) Suppose I have a bag with 4 marbles. One is red and 3 are green. Pick one marble, note the color and then put it back and pick a second marble. Find P(Both Red) = Explain your reasoning. P(Both Green) = %3D %3D
ge 2: Has the proportion of Americans that are "20-somethings" decreased? According to the US Census Bureau, 14.8% of Americans living in 2004 were "20- somethings" (between ages 20 and 29). You take a random sample of 500 Americans and find that 59 of them fall in this age range. Has the proportion of Americans ages 20-29 decreased from what it was in 2004? for this problem (z-test or t-test).
Pew Research surveyed a random sample of 1,313 U.S. adults in 2011. They asked them: "How important is it, to you personally, to be successful in a high-paying career or profession?" Importance Very important Somewhat important Not important Total Chi-square test Statistic Chi-square total female male 403 408 811 (66.1%) (58.0%)| (61.8%) 158 218 376 (25.9%) (31.0%) (28.6%) 49 77 126 (8.0%) (11.0%) (9.6%) 610 703 1313 (100%) (100%) (100%) df Value P-value 2 9.287 0.0096 We want to test if men and women have the same ideas about the importance of this kind of success. What are the hypotheses?
How do you identify the chi sq & the p-value? How will you interpret the p-value?
Can you explain 2.35
alo Smart phone: Among 248 cell phone owners aged 18-24 surveyed, 104 said their phone was an Android phone. Part: 0 / 3 Part 1 of 3 (a) Find a point estimate for the proportion of cell phone owners aged 18-24 who have an Android phone. Round the answer to at least three decimal places. The point estimate for the proportion of cell phone owners aged 18-24 who have an Android phone is Part: 1/3 Part 2 of 3 (b) Construct a 99.5% confidence interval for the proportion of cell phone owners aged 18-24 who have an Android phone. Round the answers to at least three decimal places. A 99.5% confidence interval for the proportion of cell phone owners aged 18-24 who have an Android phone is
6. A comparison of life expectancy in random samples of 40 less-developed countries and 31 industrialized countries reveals the following (fictional) data. The standard deviations are significantly different from one another. Is there a significant difference in mean life expectancy between countries with these two levels of economic development? X=life expectancy of the resident at birth. Less-Developed Countries Mean=66.1 years N=40 Standard error of the difference between means=.60 Industrialized Countries Mean=76.7 years N=31
What is the base rate(or prevalence in medical literature) and sensitivity(the percentage of individuals with a disease who are correctly classified as having the disease?)
needed help calculating B
← The results of a survey on the belief that stem cell research has merit are shown in the table below. % X 1524 SEP 28 95% CI (0.7052, 0.7434) Here, X denotes the number who believed that stem cell research has merit. Complete parts a and b below. N 2104 a. Explain how to interpret "Sample p" and "95% CI" in this table. The "Sample p" is the proportion of all respondents in the sample who believe stem cell research has merit, 1524/2104 0.72. The "95% CI" is the 95% confidence interval and it means that we can be 95% confident that the interval 0.7052 to 0.7434 contains the population proportion. (Round to four decimal places as needed.) b. What is the 95% margin of error associated with the poll? The 95% margin of error is. (Round to four decimal places as needed.) F5 6 Sample p 0.724335 tv F6 Clear all & F7 Check answer Ndi 8 DIL 9 elp students like you learn core concep for 10 level of significance and two (0-65) (0-35) 1000 Chegg Study F9 A O