Enter the exact answers. (a) What proportion of all cases had Outcome A? i (b) What proportion of all cases are in Group 1? i (c) What proportion of cases in Group 1 had Outcome B? i (d) What proportion of cases who had Outcome A were in Group 2? M.

Q: The area of the shaded region is

A: Let Z denote the Standard Normal variate i.e N(0,1)

Q: so-Z of what is 21

A:

Q: 16) n = 4; 2, 1 and 3 + 3i are zeros; f(1) =78 %3D

A:

Q: (0,0) (2,4)

A: In the given graph we have two points on line. which are (-4,2) ,(0,4)

Q: Find the rank- 1 approximation of

A:

Q: Evaluate. Use a capital C for any constant. fae 9 /6(82 – 1)(82² – 2æ + 3)° dæ (3(8x^2-2x+3)^10)/8 -

A: NOTE: Refresh your page if you can't see any equations. . ...............(1)

Q: 5. Show that 1.2+2·3+3.4+...+ (n − 1)(n) = (n³ − n)

A:

Q: 3. Solve for x. a. 3 b. 8-x x + 2 X x +4 1 x+1 = 1

A:

Q: Evaluate. 20) X +9 -dx X +5

A:

Q: a. (f+g)(-4)

A:

Q: Find the value of n(A U B) if n(A) = 8, n(B) = 13 and n(A n B) = 6. n(AUB) (Type a whole number.) =

A:

Q: 3.20) what is the remainder when 1s+85+...t100s is divided by4?

A: Given 15+25+....+1005 is divided by 4

Q: 1a.) 0x**3  + 9x**3  1b.) 4X**3  - 9x**5  1c.) (3x   + 1x**3) + 2(9x**3 +(-3x)) 1d.)…

A: 1a.) 0x**3  + 9x**3 1b.) 4X**3  - 9x**5 1c.) (3x   + 1x**3) + 2(9x**3 +(-3x))1d.)…

Q: 1.4.19 how does the solve for it ? I just stuck and confused linear algebra

A: