15. x₁ - 2x₂ + 5x3 = b₁ X1 5x₂ + 8x3 = b₂ 4x1 -3x₁ + 3x₂-3x3 = b3 1

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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F1.6 Question 15 on paper please
### Linear Systems and Matrix Equations

**11. Solve the following systems of linear equations.**

\[ 
\begin{aligned}
i. \quad x_1 + 2x_2 &= b_2 \\
x_1 + 2x_2 + b_2 &= 1 \\
b_1 &= 0, \quad b_2 = 1 
\end{aligned}
\]

\[ 
\begin{aligned}
ii. \quad b_1 &= -4, \quad b_2 = 6 
\end{aligned}
\]

\[ 
\begin{aligned}
iii. \quad b_1 &= -1, \quad b_2 = 3 
\end{aligned}
\]

\[ 
\begin{aligned}
iv. \quad b_1 &= -5, \quad b_2 = 1 
\end{aligned}
\]

**12. In Exercises 13–17, determine conditions on the \(b_i\)'s, if any, in order to guarantee that the linear system is consistent.**

\[ 
\begin{aligned}
x_1 + 3x_2 + 5x_3 &= b_1 \\
-x_1 - 2x_2 &= b_2 \\
-2x_1 + 5x_2 + 4x_3 &= b_3 
\end{aligned}
\]

\[ 
\begin{aligned}
i. \quad b_1 &= 1, \quad b_2 = 0, \quad b_3 = -1 
\end{aligned}
\]

\[ 
\begin{aligned}
ii. \quad b_1 &= 1, \quad b_2 = 0, \quad b_3 = 1 
\end{aligned}
\]

\[ 
\begin{aligned}
iii. \quad b_1 &= -1, \quad b_2 = -1, \quad b_3 = 0 
\end{aligned}
\]

**13.** 

\[ 
\begin{aligned}
x_1 + 3x_2&= b_1 \\
-2x_1 + x_2&= b_2 
\end{aligned}
\]

**14.** 

\[ 
\begin{aligned}
6x_1 - 4x_2 &= b
Transcribed Image Text:### Linear Systems and Matrix Equations **11. Solve the following systems of linear equations.** \[ \begin{aligned} i. \quad x_1 + 2x_2 &= b_2 \\ x_1 + 2x_2 + b_2 &= 1 \\ b_1 &= 0, \quad b_2 = 1 \end{aligned} \] \[ \begin{aligned} ii. \quad b_1 &= -4, \quad b_2 = 6 \end{aligned} \] \[ \begin{aligned} iii. \quad b_1 &= -1, \quad b_2 = 3 \end{aligned} \] \[ \begin{aligned} iv. \quad b_1 &= -5, \quad b_2 = 1 \end{aligned} \] **12. In Exercises 13–17, determine conditions on the \(b_i\)'s, if any, in order to guarantee that the linear system is consistent.** \[ \begin{aligned} x_1 + 3x_2 + 5x_3 &= b_1 \\ -x_1 - 2x_2 &= b_2 \\ -2x_1 + 5x_2 + 4x_3 &= b_3 \end{aligned} \] \[ \begin{aligned} i. \quad b_1 &= 1, \quad b_2 = 0, \quad b_3 = -1 \end{aligned} \] \[ \begin{aligned} ii. \quad b_1 &= 1, \quad b_2 = 0, \quad b_3 = 1 \end{aligned} \] \[ \begin{aligned} iii. \quad b_1 &= -1, \quad b_2 = -1, \quad b_3 = 0 \end{aligned} \] **13.** \[ \begin{aligned} x_1 + 3x_2&= b_1 \\ -2x_1 + x_2&= b_2 \end{aligned} \] **14.** \[ \begin{aligned} 6x_1 - 4x_2 &= b
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