2. Mr. Guo receives many spam emails each day. A random sample of12850 emails in his inbox indicates that 13 out of every 25 emails inhis inbox is spam.(a) Find a reasonable point estimate for p.(b) Mr. Guo wishes to find a 97% confidence interval for p. Are allconditions for the Large-Sample Confidence Interval met? If not,explain why.(c) Find the z critical number associated with a 97% confidence in-terval. Hint: We are looking for z such that the central area is97%.(d) Construct a central 97% confidence interval for p.A(e) What is the minimum sample size required to conservatively es- Gtimate p within .005 with 97% confidence?

Given that, No. of emails in his inbox (n) = 12850 Out of 25 emails,13 are spam. Confidence level…

Answered: (a) Find a reasonable point estimate…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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What price do farmers get for their watermelon crops? In the third week of July, a random sample of 40 farming regions gave a sample mean of x = Assume that o is known to be $1.92 per 100 pounds. $6.88 per 100 pounds of watermelon. (a) Find a 90% confidence interval for the population mean price (per 100 pounds) that farmers in this region get for their watermelon crop (in dollars). What is the margin of error (in dollars)? (For each answer, enter a number. Round your answers to two decimal places.) lower limit $ upper limit 2$ margin of error $ (b) Find the sample size necessary for a 90% confidence level with maximal error of estimate E = 0.27 for the mean price per 100 pounds of watermelon. (Enter a number. Round up to the nearest whole number.) farming regions (c) A farm brings 15 tons of watermelon to market. Find a 90% confidence interval for the population mean cash value of this crop (in dollars). What is the margin of error (in dollars)? Hint: 1 ton is 2000 pounds. (For each…
Assume that last year in a particular state there were 211 children out of 1990 who were diagnosed with Autism Spectrum Disorder. Nationally, 1 out of 88 children are diagnosed with ASD. It is believed that the incident of ASD is more common in that state than nationally. Calculate a 96% confidence interval for the percentage of children in that state diagnosed with ASD.P: Parameter What is the correct parameter symbol for this problem? What is the wording of the parameter in the context of this problem? A: Assumptions Since information was collected from each object, what conditions do we need to check? Check all that apply. n≥30n≥30 or normal population. N≥20nN≥20n n(pˆ)≥10n(p̂)≥10 σσ is known. σσ is unknown. n(1−pˆ)≥10n(1-p̂)≥10 Check those assumptions: 1. nˆpnp^= which is 2. n(1−ˆp)n(1-p^)= which is 3. NN= which is If no N is given in the problem, use 1000000N: Name the procedure The…
Assume that we want to construct a confidence interval. Do one of the following, as appropriate: (a) find the critical value ta/2. (b) find the critical value z/2, or (c) state that neither the normal distribution nor the t distribution applies. The confidence level is 95%, o is not known, and the histogram of 62 player salaries (in thousands of dollars) of football players on a team is as shown.
Determine the point estimate of the population proportion, the margin of error for the following confidence interval, and the number of individuals in the sample with the specified characteristic, x, for the sample size provided. Lower bound=0.189, upper bound=0.391, n=1000 The point estimate of the population proportion is (Round to the nearest thousandth as needed.) Part 2 The margin of error is (Round to the nearest thousandth as needed.) Part 3 The number of individuals in the sample with the specified characteristic is (Round to the nearest integer as needed.)
Is the birth rate of the infants in this sample significantly different from that of the general population at alpha level of 0.05? Explain your response.
What critical value of t* should be used for a 99.5% confidence interval for the population mean based upon a random sample of 18 observations? Find the t-table here. t* = 2.878 t* = 2.898 t* = 3.197 t* = 3.222
Allen's hummingbird (Selasphorus sasin) has been studied by zoologist Bill Alther.t Suppose a small group of 12 Allen's hummingbirds has been under study in Arizona. The average weight for these birds is x = 3.15 grams. Based on previous studies, we can assume that the weights of Allen's hummingbirds have a normal distribution, with a = 0.22 gram. When finding an 80% confidence interval, what is the critical value for confidence level? (Give your answer to two decimal places.) (a) Find an 80% confidence interval for the average weights of Allen's hummingbirds in the study region. What is the margin of error? (Round your answers to two decimal places.) lower limit upper limit margin of error (b) What conditions are necessary for your calculations? (Select all that apply.) Oo is known Oo is unknown O uniform distribution of weights O normal distribution of weights On is large (c) Interpret your results in the context of this problem. We are 80% confident that the true average weight of…
It’s not C

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