Use Table V in Appendix A to determine the t-percentile that is required to construct each of the following two-sided confidenceintervals. Round the answers to 3 decimal places.(a) Confidence level = 95%, degrees of freedom = 16(b) Confidence level = 95%, degrees of freedom = 24(c) Confidence level = 99%, degrees of freedom = 13(d) Confidence level = 99.9%, degrees of freedom = 17(a)(b)(c)(d)

a) Confidence level=95%, degree of freedom=16 b) Confidence level=95%, degree of freedom=24 c)…

Answered: Use Table V in Appendix A to determine…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Use the Student's t distribution to find tc for a 0.90 confidence level when the sample is 6. (Round your answer to three decimal places.)
A survey of randomly selected university students found that 91 of the 101 first-year students and 96 of the 136 second-year students surveyed had purchased used textbooks in the past year. (a) Construct a 95% confidence interval for the difference the proportions of first-year and second-year university students who purchased used textbooks. (Round your answers to 4 decimal places, if needed.) Answer: (b) If a 98% confidence interval for the difference in proportion of first-year and second-year university students who purchased used textbooks is (0.0809, 0.3093). Give an interpretation of this confidence interval. O We are 98% confident that the first-year students at this university bought between 8.09% and 30.93% more used textbooks than second-year students. O We know that 98% of the first-year students bought between 8.09% and 30.93% higher than the proportion of second-year students who bought used textbooks. O We are 98% confident that, at this university, the proportion of…
d) Construct a 90% confidence interval for Hcommunity college - Hno transfer to approximate the mean additional time it takes to complete a bachelor's degree if you begin in community college. The confidence interval is the range from to (Round to three decimal places as needed.)
During the 2009 holiday season, 436 randomly sampled American adults were surveyed regarding their average spending on Black Friday. A 95% confidence interval based on this sample is ($80.31,$89.11). (c) Determine the sample mean x and the sample standard deviation s of the sample. (d) Which would be the confidence level corresponding to an interval ($81.27,$88.15) for the data found in (c)? (e) If the values of the sample mean and sample standard deviation found in (c) do not change, find the sample size N for which a 99% confidence interval would have a margin of error smaller than 5.
Construct the 99.5% confidence interval for the difference p, - p, when x, = 50, n, = 75, x, = 65, and n, = 151. Round the answers to three decimal places. A 99,5% confidence interval for the difference between the two proportions is
Echinacea is widely used as an herbal remedy for the common cold, but does it work? In a double-blind experiment, healthy volunteers agreed to be exposed to common-cold-causing rhinovirus type 39 and have their symptoms monitored. The volunteers were randomly assigned to take either a placebo or an echinacea supplement daily for 5 days following viral exposure. Among the 103 subjects taking a placebo, 88 developed a cold, whereas 44 of the 48 subjects taking echinacea 1 developed a cold.
Use the Student's t distribution to find tc for a 0.95 confidence level when the sample is 17. (Round your answer to three decimal places.)
Use the Student's t distribution to find tc for a 0.90 confidence level when the sample is 25. (Round your answer to three decimal places.)
Use the Student's t distribution to find tc for a 0.95 confidence level when the sample is 3. (Round your answer to three decimal places.)
At a large high school, an assistant principal wants to know how intelligent the students at the school are. An intelligence test is administered to an SRS of 50 students, out of over 2000 students. The mean score was 115 and the standard deviation was 15. Construct a 99% confidence interval for the mean score of all students in the school. A) (109.32, 120.69) B) (119.58, 123.50) C) (110.87, 129.41) D) Can not be determined from the information given.
Use the Student's t distribution to find tc for a 0.95 confidence level when the sample is 13. (Round your answer to three decimal places.)

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