Please use the formula sheet to solveA feed of A with a volumetric flowrate of 4 L/min and an initial concentration of 1 mol/L enters a2 liter mixed flow reactor and the following reaction occurs: ? → ?. The concentration of Aleaving the reactor is 0.01 mol/L. Calculate the reaction rate of A (rA). n = 0-TA = kn = 1-TA = KCAn = 2-TA = KC²any n=-TAkCKTCAOTable 5.1 Performance Equations for nth-order Kinetics and A = 0Plug Flow or BatchCAO - CACAOKT = lnCAOCAkTCao == InCAOCA(n − 1)Chokr=8.1 Integral Table= XA11-XA- CAΧΑ1-XAC₁ 1-nA0/- 1 = (1 - XA)¹-n – 1pX₂(20)(3.12)dX(1(3.16)dX(4=(x)In1- X(3.29)1- Xx₁²01²²x²-1-²-²₂2-1-²XdXfax-xX1- XKTCAOdX²14xx - ² m (1 + ex)= ln+ EXKkT=KT=KT =САО - САCAOCAO - CACANote: for batch reactor t = tVfor Plug flow reactor t = where V is the reactor volume and v is the volumetric flowrateVFAo = vCAOMixed Flow(Cao – CA)-ÁO - CACA= XAXA1 - XAXACao(1 − Xa)ΧΑCho (1 − XA)"(14a)(15)

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Answered: A feed of A with a volumetric flowrate…

Introduction to Chemical Engineering Thermodynamics

8th Edition

ISBN:9781259696527

Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart

Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart

Chapter1: Introduction

Section: Chapter Questions

Problem 1.1P

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Question

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Please use the formula sheet to solve

A feed of A with a volumetric flowrate of 4 L/min and an initial concentration of 1 mol/L enters a
2 liter mixed flow reactor and the following reaction occurs: ? → ?. The concentration of A
leaving the reactor is 0.01 mol/L. Calculate the reaction rate of A (r_A).

n = 0
-TA = k
n = 1
-TA = KCA
n = 2
-TA = KC²
any n
=
-TA
kC
KT
CAO
Table 5.1 Performance Equations for nth-order Kinetics and A = 0
Plug Flow or Batch
CAO - CA
CAO
KT = ln
CAO
CA
kTCao =
= In
CAO
CA
(n − 1)Chokr=
8.1 Integral Table
= XA
1
1-XA
- CA
ΧΑ
1-XA
C₁ 1-n
A0/
- 1 = (1 - XA)¹-n – 1
pX₂
(20)
(3.12)
dX
(1
(3.16)
dX
(4=(x)
In
1- X
(3.29)
1- X
x₁²01²²x²-1-²-²₂2-1-²X
dX
fax-x
X
1- X
KT
CAO
dX
²14xx - ² m (1 + ex)
= ln
+ EX
KkT=
KT=
KT =
САО - СА
CAO
CAO - CA
CA
Note: for batch reactor t = t
V
for Plug flow reactor t = where V is the reactor volume and v is the volumetric flowrate
V
FAo = vCAO
Mixed Flow
(Cao – CA)
-
ÁO - CA
CA
= XA
XA
1 - XA
XA
Cao(1 − Xa)
ΧΑ
Cho (1 − XA)"
(14a)
(15)

Expert Solution

Step 1: Given data:

$T h e space v o l u m e t r i c space f e e d space o f space t h e space r e a c tan t space t o space t h e space r e a c t o r comma v subscript o equals 4 fraction numerator L over denominator m i n end fraction T h e space v o l u m e space o f space t h e space m i x e d space f l o w space r e a c t o r comma V equals 2 space L T h e space i n i t i a l space c o n c e n t r a t i o n space o f space t h e space r e a c tan t space A comma C subscript A o end subscript equals 1 fraction numerator m o l over denominator L end fraction T h e space c o n c e n t r a t i o n space o f space t h e space r e a c tan t space A space l e a v i n g space t h e space r e a c t o r comma C subscript A equals 0.01 fraction numerator m o l over denominator L end fraction$