The gas phase reversible reaction A+B +→ D + E is taking place in a reactor at 2 atm, abs. Some of the concentrations are given below for one run: Component Reactor Feed Equilibrium (mols fraction) (mole fraction) 0.2 0.27 0.18 A 0.098 nd nd nd D E 0.07 bal nd Table 1- Reactor data at 300C and 2 atm. Analysis by GC. nd is not determined. Component I does not participate in the reaction and can be considered inert. The equilibrium constant is given by the following equation Pp PE PAPB Where P; is the partial pressure of component i. Determine the: a) partial pressure (atm) of A in the equilibrium product b) equilibrium percent conversion of the limiting component c) percent excess of the non-limiting component d) mole percent of B in the equilibrium mixture e) equilibrium constant for this temperature
The gas phase reversible reaction A+B +→ D + E is taking place in a reactor at 2 atm, abs. Some of the concentrations are given below for one run: Component Reactor Feed Equilibrium (mols fraction) (mole fraction) 0.2 0.27 0.18 A 0.098 nd nd nd D E 0.07 bal nd Table 1- Reactor data at 300C and 2 atm. Analysis by GC. nd is not determined. Component I does not participate in the reaction and can be considered inert. The equilibrium constant is given by the following equation Pp PE PAPB Where P; is the partial pressure of component i. Determine the: a) partial pressure (atm) of A in the equilibrium product b) equilibrium percent conversion of the limiting component c) percent excess of the non-limiting component d) mole percent of B in the equilibrium mixture e) equilibrium constant for this temperature
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Transcribed Image Text:The gas phase reversible reaction A+B +→D + E is taking place in a reactor at 2 atm, abs. Some of the concentrations are given below
for one run:
Component Reactor Feed
Equilibrium
(mols fraction) (mole fraction)
0.098
A
0.2
0.27
nd
nd
nd
nd
Table 1- Reactor data at 300C and 2 atm. Analysis by GC. nd is not determined. Component I does not participate in the
D
0.18
E
0.07
bal
reaction and can be considered inert.
The equilibrium constant is given by the following equation
Pp PE
PAPB
Where P; is the partial pressure of component i.
Determine the:
a) partial pressure (atm) of A in the equilibrium product
b) equilibrium percent conversion of the limiting component
c) percent excess of the non-limiting component
d) mole percent of B in the equilibrium mixture
e) equilibrium constant for this temperature
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