A fatigue crack growth test is being carried out on a large steel plate containing a 2 mm edge crack. The growth of cracks can be well represented by the Paris Law da = A(AK), where A is a constant (A = 6.6 x 10-13 (MPa)-4 m cycle ¹) and AK = Kmax AN Kmirr - If the plate is subjected to a fatigue stress for which max = 120 MPa and a ratio R = -0.25 (R=0min/max) at a frequency of 2 Hz (2 cycles per second), how long will the crack grow to after 10 hours? Note that: ja; da = [1-4] af and K for the edge crack is K = 1.12 σ√(ла) 8 mm 7.2 mm 2.6 mm 3 mm 10 mm

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
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A fatigue crack growth test is being carried out on a large steel plate containing a 2
mm edge crack. The growth of cracks can be well represented by the Paris Law
da
A(AK), where A is a constant (A = 6.6 × 10-13 (MPa)-4 m cycle-1) and AK =
Kmax
AN
-
=
Kmin
If the plate is subjected to a fatigue stress for which max = 120 MPa and a ratio R=
-0.25 (R= min/max) at a frequency of 2 Hz (2 cycles per second), how long will the
crack grow to after 10 hours?
Note that:
fai da = [₁
1
af
and K for the edge crack is K= 1.12 σ√(ла)
8 mm
7.2 mm
2.6 mm
3 mm
10 mm
Transcribed Image Text:A fatigue crack growth test is being carried out on a large steel plate containing a 2 mm edge crack. The growth of cracks can be well represented by the Paris Law da A(AK), where A is a constant (A = 6.6 × 10-13 (MPa)-4 m cycle-1) and AK = Kmax AN - = Kmin If the plate is subjected to a fatigue stress for which max = 120 MPa and a ratio R= -0.25 (R= min/max) at a frequency of 2 Hz (2 cycles per second), how long will the crack grow to after 10 hours? Note that: fai da = [₁ 1 af and K for the edge crack is K= 1.12 σ√(ла) 8 mm 7.2 mm 2.6 mm 3 mm 10 mm
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