Determine the percentage of ductility of a metal alloy having the following tensile stress-strain diagram. Tensile stress-strain diagram 450 400 350 300 250 200 150 200 100 50 0.05 0.1 0.15 0.2 0.25 03 0.35 0.4 Strain Stress (Mpa) 我

Determine the percentage of ductility of a metal alloy having the following tensile stress-strain diagram. Tensile stress-strain diagram 450 400 350 300 250 200 150 200 100 50 0.05 0.1 0.15 0.2 0.25 03 0.35 0.4 Strain Stress (Mpa) 我

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Answer should be in MPa
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1. For the stress-strain curve shown below, please estimate the properties indicated. (a) Fracture Strain Please do your work on a separate sheet of paper, and put your answers in the boxes on the right. Be sure to include the proper symbol and units. Stress Strain 70 60 50 Stress (ksi) 240 30 20 10 70 0 0.000 60 50 Stress (ksi) 40 20 10 KULL 0 0.000 0.010 0.050 0.100 Strain (in/in) Stress Strain 0.020 0.030 Strain (in/in) 0.040 0.150 0.050 (b) Ultimate Tensile Stress (c) Fracture Stress (d) Proportional Limit (e) Elastic Modulus (1) Yield Stress (g) Tensile Toughness (Modulus of Toughness) (h) Modulus of Resilience
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A bronze alloy specimen having a diameter of 12.8 mm and a gage length of 50 mm was tested to fracture. Stress and strain data obtained during the test are shown. Determine the fracture stress. Stress (MPa) 50 40- 30- 20- 10- 0 0 0 Upper scale O 59 MPa O 24 MPa O 40 MPa O 50 MPa O 33 MPa 0.100 0.005 Lower scale 0.200 0.010 Strain (mm/mm) 0.300 0.015 0.400 0.020
640 480 160 0.002 0,004 0.006 0.008 0.010 Strain (mm/mm) A tensile test specimen of Aluminum alloy having a gauge length of 280 mm was tested to fracture. Stress and strain data obtained during the test are shown in the attached Figure. **Answers are approximate - do your best to read the graph. Determine: (a) the modulus of elasticity in GPa (4sigs). Enter this value into D2L answer box. (b) the proportional limit in MPa (3sigs). (c) the ultimate strength in MPa (3sigs). (d) Ductility of material based on percent elongation. (3sigs) Your Answer: Stress (MPa)
The answer is one of the options below please solve carefully and circle the correct option Please write clear .
During a test, a copper specimen alloy having a diameter of 10.2 mm is applied with a tensile load of 8900 N. Given a maximum allowable elongation of 0.25 mm, determine the maximum length (mm) of the specimen before deformation.
From the shear stress - shear strain diagram shown below, all the following are true except: Shear Stress (MPa) 500 450 400 350 300 250 200 150 100 50 0. 0.2 0.4 0.6 0.8 1.2 1.4 1.6 1.8 Shear Strain (rad) Shear Stress-Strain Curve for Brass Select one: O a. Shear stress and Shear strain are 430 MPa and 1.72 rad at fracture. O b. Shear stress and Shear strain are 250 MPa and 0.05 rad at Yielding. Oc. The elastic zone ends at a shear stress of 400 MPa and shear strain of 1 rad Od. The ultimate Shear stress and Shear strain are 430 MPa and 1.72 rad.
5. Consider a cylindrical specimen of a steel alloy (Figure 6.22) 10 mm in diameter and 75 mm long that is pulled in tension. Determine its elongation when a load of 20,000 N is applied. Stress (MPa) 600 500 400 300 200 100 0 0.00 0.04 Stress (MPa) 500 400 300 200 100 0.000 0.002 0.004 0.006 0.08 Strain Strain 0.12 0.16 0.20 Figure 6.22 Tensile stress-strain behavior for a steel alloy.
For a steel element with a 0.2% steel characteristic, a stress test was applied and the analysis of the data thrown by the material is required in terms of a variation of force and the respective deformations. Determine the following: A.Determine the percentage elongation at the point where the part develops the fracture. B.Construct the “Stress-Strain” diagram C.Maximum tensile strength of the part.
Learning Goal: A material is homogenous and isotropic when it has a modulus of elasticity that does not vary with direction and it has uniform properties throughout. When a point in a material is subjected to only normal stresses in three dimensions, but they are not necessarily equal, the state is called triaxial stress. When the response of the material is linear elastic, the strains along the three axes can be calculated using a generalized form of Hooke's law. Each strain depends on all three stresses because of the Poisson effect. €1 Figure 1 [0₂ - V (O₂ +0₂)] a 1 of 1 A cube is subjected to stresses with magnitudes a = 16 MPa, b = 26 MPa, and c = 5 MPa (Figure 1). What is the strain in the y-direction? Let E = 200 GPa and v= 0.26. Express your answer to three significant figures. ► View Available Hint(s) Submit VE ΑΣΦ Part B - Change in volume f change in volume = vec The cube from Part A originally has side length 3.2 cm . What is the change in volume of the cube under the given…