A– EVEN: A 1.5kN bar AB carries a load F = 65 kN 4m vertical force at A. The bar is supported by a pin at B and the 12.5-mm. diameter cable CD. 3m 3m Find the a. tension in the cable CD in kN. b. Horizontal reaction at B in kN. 100 mm c. Vertical reaction at B in kN. d. Tensile stress in the cable in MPa. e. Shearing stress at B in MPa. 85 mm 12.5-mm dia. Detail at B
A– EVEN: A 1.5kN bar AB carries a load F = 65 kN 4m vertical force at A. The bar is supported by a pin at B and the 12.5-mm. diameter cable CD. 3m 3m Find the a. tension in the cable CD in kN. b. Horizontal reaction at B in kN. 100 mm c. Vertical reaction at B in kN. d. Tensile stress in the cable in MPa. e. Shearing stress at B in MPa. 85 mm 12.5-mm dia. Detail at B
Mechanics of Materials (MindTap Course List)
9th Edition
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Barry J. Goodno, James M. Gere
Chapter2: Axially Loaded Members
Section: Chapter Questions
Problem 2.3.19P: Repeat Problem 2.3-18, but assume that the bar is made of copper alloy. Calculate the displacements...
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answer d and e
![Free body diagram of the bar is shown below :
T Sins
Rv
3m
T Cose
Rh
Now, in traingle BCD;
tane =
0 = 53. 13°
Now, for the cquilibrium of the bar;
E My = 0
Fx6+Wx 3 – T Sine x 3 – T Cose x 0 = 0
65 x6+1.5 x 3 - Tx Sin 53. 13 x 3 = 0
T = 164. 3752 kN
(b) EF, = 0
Rh – T Cos0 = 0
Rh = 164. 3752 x Cos 53. 13
Rh = 98. 6254 kN
(:) =
c) E F, = 0
T Sine – Ry –F-W = 0
R, = 164. 3752 x Sin 53. 13 – 65 – 1.5
R, = 65 kN
Hence, tension in cable CD = 164.3752 kN, Horizontal reaction at B
= 98. 6254 kN & Vertical reaction at B = 65 kN](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F31a26f9d-2356-4f2a-a141-f63fa034ca94%2Fe6ad0884-3d4a-4fd1-8f80-e0b6dd0863b7%2Fznpbsog_processed.png&w=3840&q=75)
Transcribed Image Text:Free body diagram of the bar is shown below :
T Sins
Rv
3m
T Cose
Rh
Now, in traingle BCD;
tane =
0 = 53. 13°
Now, for the cquilibrium of the bar;
E My = 0
Fx6+Wx 3 – T Sine x 3 – T Cose x 0 = 0
65 x6+1.5 x 3 - Tx Sin 53. 13 x 3 = 0
T = 164. 3752 kN
(b) EF, = 0
Rh – T Cos0 = 0
Rh = 164. 3752 x Cos 53. 13
Rh = 98. 6254 kN
(:) =
c) E F, = 0
T Sine – Ry –F-W = 0
R, = 164. 3752 x Sin 53. 13 – 65 – 1.5
R, = 65 kN
Hence, tension in cable CD = 164.3752 kN, Horizontal reaction at B
= 98. 6254 kN & Vertical reaction at B = 65 kN
![D.
A - EVEN:
A 1.5kN bar AB carries a load F = 65 kN
vertical force at A. The bar is supported by a
pin at B and the 12.5-mm. diameter cable
CD.
4m
3m
3m
Find the
a. tension in the cable CD in kN.
B
b. Horizontal reaction at B in kN.
100 mm
F
c. Vertical reaction at B in kN.
d. Tensile stress in the cable in MPa.
e. Shearing stress at B in MPa.
85 mm
12.5-mm dia.
Detail at B](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F31a26f9d-2356-4f2a-a141-f63fa034ca94%2Fe6ad0884-3d4a-4fd1-8f80-e0b6dd0863b7%2Fmgs0wah_processed.png&w=3840&q=75)
Transcribed Image Text:D.
A - EVEN:
A 1.5kN bar AB carries a load F = 65 kN
vertical force at A. The bar is supported by a
pin at B and the 12.5-mm. diameter cable
CD.
4m
3m
3m
Find the
a. tension in the cable CD in kN.
B
b. Horizontal reaction at B in kN.
100 mm
F
c. Vertical reaction at B in kN.
d. Tensile stress in the cable in MPa.
e. Shearing stress at B in MPa.
85 mm
12.5-mm dia.
Detail at B
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