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a End cap of area n 4.0 × 10-4 m² a 91 o = 2.0 × 10-6 C/m² (c) (d) + + + + + + + + + + + + + + Conductor

a End cap of area n 4.0 × 10-4 m² a 91 o = 2.0 × 10-6 C/m² (c) (d) + + + + + + + + + + + + + + Conductor

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Find the electric flux through the closed surface whose cross sections are shown in the figure. In the drawings, the charges have the following values:

q1= -20.5 nC; q2 = +29 nC; q3 = +4.1 μC; q4 = -2.7 μC; q5 = +4.8 μC

(a) What is the total electric flux through the closed surface shown in part (a) of the figure? Answer in units of Nm2.

(b) What is the total electric flux through the closed surface shown in part (b) of the figure? Answer in units of Nm2.

(c) What is the total electric flux through the closed surface shown in part (c) of the figure? Answer in units of Nm2.

(d) Part (d) of the figure shows a portion of an indefinitely long conductor. We are only interested in the colored rectangle with the area shown that contains some positive charge. The conductor has a charge per unit area σ=2.0 X 10-6 C/m2. What is the total electric flux through the rectangular cross-section? Answer in units Nm2/C.

91 94 93 92 + 95 (a) (b) End cap of area сар ~ 4.0 × 10-4 m2 91 o = 2.0 × 10 C/m2 (c) (d) + + + + + + + 8. Conductor + + + + + + +
Transcribed Image Text:91 94 93 92 + 95 (a) (b) End cap of area сар ~ 4.0 × 10-4 m2 91 o = 2.0 × 10 C/m2 (c) (d) + + + + + + + 8. Conductor + + + + + + +
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