Answered: a End cap of area n 4.0 × 10-4 m² a 91…

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a End cap of area n 4.0 × 10-4 m² a 91 o = 2.0 × 10-6 C/m² (c) (d) + + + + + + + + + + + + + + Conductor

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Question

Find the electric flux through the closed surface whose cross sections are shown in the figure. In the drawings, the charges have the following values:

q1= -20.5 nC; q2 = +29 nC; q3 = +4.1 μC; q4 = -2.7 μC; q5 = +4.8 μC

(a) What is the total electric flux through the closed surface shown in part (a) of the figure? Answer in units of Nm².

(b) What is the total electric flux through the closed surface shown in part (b) of the figure? Answer in units of Nm2.

(d) Part (d) of the figure shows a portion of an indefinitely long conductor. We are only interested in the colored rectangle with the area shown that contains some positive charge. The conductor has a charge per unit area σ=2.0 X 10^-6 C/m². What is the total electric flux through the rectangular cross-section? Answer in units Nm²/C.

91
94
93
92 +
95
(a)
(b)
End cap of area
сар
~ 4.0 × 10-4 m2
91
o = 2.0 × 10 C/m2
(c)
(d)
+ + + + + + +
8.
Conductor
+ + + + + + +

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