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Two Hat conductors are placed with their in- ner faces separated by 16 mm. If the surface charge density on inner face A is 105 pC/m and on inner face B is -105 pC/m², calculate the electric po- tential difference AV VA – VB- Use 8.85419 x 10¬2 c² /Nm2. Answer in units of V. %3D

Two Hat conductors are placed with their in- ner faces separated by 16 mm. If the surface charge density on inner face A is 105 pC/m and on inner face B is -105 pC/m², calculate the electric po- tential difference AV VA – VB- Use 8.85419 x 10¬2 c² /Nm2. Answer in units of V. %3D

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Two flat conductors are placed with their in- ner faces separated by 16 mm. If the surface charge density on inner face A is 105 pC/m and on inner face B is -105 pC/m², calculate the electric po- tential difference AV VA VB- Use €0 = 8.85419 x 10¬12 c² /Nm². Answer in units of V. %3D
Transcribed Image Text:Two flat conductors are placed with their in- ner faces separated by 16 mm. If the surface charge density on inner face A is 105 pC/m and on inner face B is -105 pC/m², calculate the electric po- tential difference AV VA VB- Use €0 = 8.85419 x 10¬12 c² /Nm². Answer in units of V. %3D
Expert Solution
Step 1

Given

Separation between the two plates is d=16 mm=16×10-3 m

Magnitude of charge density of the two plates is σ=105 pC/m2=105×10-12 C/m2

 

We have to calculate the potential difference between the two plates.

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