The volume charge density of the long hollow cylinder, shown in the figure below, is rho= 4 ×10^−5 C/m^3 . Let a be the inner radius and b be the outer (total) radius. If a= 10 cm and b= 15 cm. Find the electric field at: a) r=5 cm b) r=12 cm c) r=25 cm
The volume charge density of the long hollow cylinder, shown in the figure below, is rho= 4 ×10^−5 C/m^3 . Let a be the inner radius and b be the outer (total) radius. If a= 10 cm and b= 15 cm. Find the electric field at:
a) r=5 cm
b) r=12 cm
c) r=25 cm


Gauss Law for electrostatics in integral form is used to find the electric field at a point when the charge distribution is given.
where Ven is the volume enclosed by the gaussian surface
Form this formula, to find electric field at a point r, we use a gaussian surface(which is a cylinder in this case) of radius r and length L. The electric field is always constant at and perpendicular to gaussian surface so it is along ds. And integral over ds is total area of gaussian cylindrical surface which is
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