The volume charge density of the long hollow cylinder, shown in the figure below, is rho= 4 ×10^−5 C/m^3 . Let a be the inner radius and b be the outer (total) radius. If a= 10 cm and b= 15 cm. Find the electric field at:  a) r=5 cm  b) r=12 cm c) r=25 cm

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The volume charge density of the long hollow cylinder, shown in the figure below, is rho= 4 ×10^−5 C/m^3 . Let a be the inner radius and b be the outer (total) radius. If a= 10 cm and b= 15 cm. Find the electric field at: 

a) r=5 cm 

b) r=12 cm

c) r=25 cm

Expert Solution
Step 1: Gauss Law for electrostatics in integral form is used to find the electric field at a point

Gauss Law for electrostatics in integral form is used to find the electric field at a point when the charge distribution is given.

contour integral subscript S E with rightwards arrow on top times d s with rightwards arrow on top equals 1 over ϵ subscript 0 integral subscript V rho d tau equals 1 over ϵ subscript 0 q subscript e n end subscript equals 1 over ϵ subscript 0 rho V subscript e n end subscript

where Ven is the volume enclosed by the gaussian surface

Form this formula, to find electric field at a point r, we use a gaussian surface(which is a cylinder in this case) of radius r and length L. The electric field is always constant at and perpendicular to gaussian surface so it is along ds. And integral over ds is total area of gaussian cylindrical surface which is left parenthesis 2 cross times p i cross times r L right parenthesis

ー_pven

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