A dumpy level is setup at one end of a line 120m long for the purpose of determining the instrument's stadia interval factor. The line is marked by hubs at every 30m and a stadia rod is held at each hub. The stadia intercepts at each location of the rod were observed as follows: 0.308, 0.613, 0.918, and 1.222meters respectively. The average value of the instruments stadia interval factor is?

Q: 5. 4

A: Since the question number to be solved is not specified, the solution for figure 5 is as follows:…

Q: The following is the bearing and length measurements of an opentraverse A) Determine the latitude…

A: The latitude of the traverse line is extend on the north and south direction and departure of the…

Q: Determine the X coordinates of the centroid of the trapezoidal area shown.

A: Given data : The given figure in divided into Rectangle and Triangle Rectangle: Width (B)=120 mm…

Q: Column CD in the unbraced frame is oriented with major-axis bending and is a W12x106. Using the…

A: Direct analysis method The Direct Analysis Method originally appears as an alternative method of…

Q: 1/2x10ft

A: We are given: 1/2×10 ft   The given expression is equivalent to computing half the length of 10 f.

Q: x; ]] a» a» dz || X2 a3 a a33

A: For calculation assume,

Q: Determine number of external indeterminacy

A: Given data : Number of external support reaction (R)=3+3=6 m=Number of member connected at hinge…

Q: Calculate the y-coordinate of the centroid of the shaded area. The triangle is equilateral.…

A:

Q: Find the centroid of the following cross-sections and planes.

A: Centrodal distanceX = 5.333 inY = 5.667 inExplanation:Step 1:Step 2:

Q: 1. GIVEN: REQOIREO: yo l0". 7,9 to locete the centreid t 6"

A: To find centroid

Q: Find the centroid for the shaded area

A: Given Diagram with dimensions    To find  Centroid of the shaded area

Q: Locate the centroid 10 mm 20 mm 10 mm 10 mm 20 mm 50 mm y

A:

Q: Determine the centroid of the / ?figure presented in below 1.8 1n 1m1 2m 3m 2 2m 1m 0.5m X >X

A:

Q: Fo B - P 800 mm C -600 mm

A:

Q: Assignment 2.: A line CD, 60mm long, is perpendicular to VP and parallel to HP. It is 20 mm above…

A:

Q: A C L- (2) B "1-12- -L/2→ C x

A:

Q: Determine y for the area shown y 1" 1" in .5" 1" 2" 2" X

A:

Q: 1⁄6 yard +3⁄8 yard

A:

Q: From the rectangular area shown a semi-circle of radius 4 cm is removed. Locate the centroid, (C),…

A:

Q: Draw the Orthographic Projections (Top View, Front View, Side View) For the Shapes Shown Below,…

A:

Q: midpoint approximation

A: Midpoint Approximation: The midpoint approximation or the midpoint rule is used for calculating the…

Q: locate the centroid area of the plate, all the unit is in mm.

A: Labelled diagram of the different section -

Q: 6"

A:

Q: BEAUTIFUL 01/ Construct Polynomial Forth function gases in cas, within [0, 1]ns4

A:

Q: 05 Find the XT 0.5 1.5 3 2.5

A:

Q: * Dount command Creates a filled circle or a filled ring O a filled circle or a wide ring. a wide…

A:

Q: Find the domains of: f(x)=- x - 9 a. {x\x€R, x#9} b. {x|x€R, x#-3, x#3} c. {x|x€R, x+-3, x # 3, x #…

A: Hello dear this is the solution of your problem The answer is found to be Option (b)  For…

Q: 31⁄5 / 4⁄7

A: 31/5=6.2 4/7=0.571

Q: Q1: determaine the coordinates of the centeroid of the shaded area 20 40 50 20 40 30 140

A: The polar coordinate system is a method to calculate points in the system location by proper…

Q: 65 degree 6' - 17 degree 54'

A: 1 degree = 60' 65 degree 6' = 64 degree 66'

Q: +y") dx ly

A:

Q: PROBLEM 2: Determine Ix and Tx.

A: given- a plane figure to find- M.O.I  about X-axis and centroidal axis.

Q: نقطتان )2( Shows polygon with the followng :Find the area (x,y) 2 1.8 1.6- 1.4- 1.2 0.8 0.6- 0.4…

A: answer is option a.)   Matlab command window picture is attached below

Q: Convert 36° 19' to decimal degree form.

A: Given data: θ=36∘19'

Q: The representation of the hinge lines of the glass box in a drawing are known as lines. ....** .....…

A: The glass box concept is used in orthographic projection. When the glass box is visualized, then…

Q: 80 38 24 340 R24 25 R40 130

A: It is not possible that every command and steps that is used in the drawing is to write down here…

Types of Composite

Composite materials are formed by merging two components that have different chemical and physical properties. The merged output is termed as a composite, whose properties are completely different from the individual components. Composite materials also have better strength than the individual components.Composite materials usually have two main parts, reinforcement material, and matrix material. The matrix material acts as a binder and surrounds the fiber of another material that bears a much higher strength. This material is known as the reinforcement material. The matrix materials are usually high-strength additives resins, while the fibers of the reinforced material can be random, oriented, and in a mat format.Composite materials are also known as fiber-reinforced composite polymers because they are composed of the polymer matrix which is reinforced to laboratory-created fibers or naturally occurring fibers, such as glass fibers, carbon fibers, or aramid fibers. Under the application of external loads, the matrix material absorbs and transfers the loads to the fibers, these fibers in return provide good compressive strength, tensile strength, and stiffness to the fiber-reinforced composite materials.Depending upon the matrix and the reinforcement material, different properties can be induced to the fiber-reinforced composite materials, including good corrosion resistance properties. The most common matrix material is the resin while the glass fibers act as the reinforcement material. Strong fibers provide strength and stiffness to the composite materials while, a soft and flexible resin provides shape to the composite materials.