A drying oven consists of a long semicircular duct of diameter D=1 m. Materials to be dried cover the base of the oven while the wall is maintained at 1200 K. Length of the oven (into paper direction) is 1 m. Water coated material is maintained at 325 K. Assume both the wall and the material to be blackbodies. (1) What is heat transfer rate? (2) Given at temperature 325 K, water needs heat 2.378 × 106 J/kg in order to be dried (from liquid water to steam). How much water can be dried per second based on the heat transfer rate from (1)? T₁ = 1200 K T₂ = 325 K — D = 1 m D= m→

Elements Of Electromagnetics
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A drying oven consists of a long semicircular duct of diameter D=1 m. Materials to be dried cover
the base of the oven while the wall is maintained at 1200 K. Length of the oven (into paper
direction) is 1 m. Water coated material is maintained at 325 K. Assume both the wall and the
material to be blackbodies.
(1) What is heat transfer rate?
(2) Given at temperature 325 K, water needs heat 2.378 × 106 J/kg in order to be dried (from
liquid water to steam). How much water can be dried per second based on the heat transfer rate
from (1)?
T₁ = 1200 K
T₂ = 325 K
— D = 1 m
D= m→
Transcribed Image Text:A drying oven consists of a long semicircular duct of diameter D=1 m. Materials to be dried cover the base of the oven while the wall is maintained at 1200 K. Length of the oven (into paper direction) is 1 m. Water coated material is maintained at 325 K. Assume both the wall and the material to be blackbodies. (1) What is heat transfer rate? (2) Given at temperature 325 K, water needs heat 2.378 × 106 J/kg in order to be dried (from liquid water to steam). How much water can be dried per second based on the heat transfer rate from (1)? T₁ = 1200 K T₂ = 325 K — D = 1 m D= m→
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