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Surface 3 T= 1200K E = 0.8 %3D Surface 1 Surface 2 q= 100W/m? E = 0.6 Perfectly insulated E = 0.8

Surface 3 T= 1200K E = 0.8 %3D Surface 1 Surface 2 q= 100W/m? E = 0.6 Perfectly insulated E = 0.8

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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5. (25%) A frustum of a cone has its base heated as shown in Figure 2. The top surface is held at 1200K while the side is perfectly insulated. Surfaces 1, 2, and 3 are assumed gray and diffuse. What are the temperatures of surface 1 and 2? If the emissivity of surface 2 changes from 0,8 to 0.6, will the temperature of surface 2 change to different value? The radius of upper circle is 1 m and the radius of lower circle is 3 m. The height of frustum is 4 m. Surface 3 T= 1200K 8 = 0.8 Surface 1 Surface 2 q= 100W/m? 8 = 0.6 Perfectly insulated ɛ = 0.8
Transcribed Image Text:5. (25%) A frustum of a cone has its base heated as shown in Figure 2. The top surface is held at 1200K while the side is perfectly insulated. Surfaces 1, 2, and 3 are assumed gray and diffuse. What are the temperatures of surface 1 and 2? If the emissivity of surface 2 changes from 0,8 to 0.6, will the temperature of surface 2 change to different value? The radius of upper circle is 1 m and the radius of lower circle is 3 m. The height of frustum is 4 m. Surface 3 T= 1200K 8 = 0.8 Surface 1 Surface 2 q= 100W/m? 8 = 0.6 Perfectly insulated ɛ = 0.8
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