A distributed load and a force is applied to a beam, where a = 2 m, b = 7 m, c= 3 m, w = 2 N/m, F = 5 N, and 0 = 45°. W F • P Determine the internal normal force (N), shear force (V), and moment (M) at point P, located at distance x = 4 m from the fixed support. (Note: Remember the sign conventions.) N = number (rtol=0.01, atol=1e-05) V = number (rtol=0.01, atol=1e-05) N M = number (rtol=0.01, atol=1e-05) N'm

A distributed load and a force is applied to a beam, where a = 2 m, b = 7 m, c= 3 m, w = 2 N/m, F = 5 N, and 0 = 45°. W F • P Determine the internal normal force (N), shear force (V), and moment (M) at point P, located at distance x = 4 m from the fixed support. (Note: Remember the sign conventions.) N = number (rtol=0.01, atol=1e-05) V = number (rtol=0.01, atol=1e-05) N M = number (rtol=0.01, atol=1e-05) N'm

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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y M C F1 L1 F2 L2 B a A a D A
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Im doing a shear and moment calculation for a problem graphically and keep getting a negative sign in my moment calculation where I should be getting a postive sign. I know that the integral of my shear calculation is going to be my moment equation but I always use this to "check" myself against my work after I do my standard summation of moments about a point. I KNOW I SHOULD be getting M_2(x) = -.5x^2 + 2x + c but as you can see by my work I keep getting a "-2x". Why is this and where am I going wrong?