A disk between vertebrae in the spine is subjected to a shearing force of 600 N. Find its shear deformation, taking it to have the shear modulus of 1×109 N/m2 . The disk is equivalent to a solid cylinder 0.700 cm high and 4.00 cm in diameter.

Q: The total cross-sectional area of the load-bearing calcified portion of the two forearm bones…

A: Cross-sectional area is Initial velocity is Final velocity is Time is Mass is Note:Find:The…

Q: A child slides across a floor in a pair of rubber-soled shoes. The frictional force acting on each…

A: NOTE: As per bartleby guidelines we can answer only first question. For remaining questions please…

Q: The Young’s modulus for steel is at most 215 GPa (1 GPa= 109 N/m2).  If you apply a force of 50.0…

A: Given quantities: Young's modulus of steel (Y) = 215 GPa Applied force (F) = 50 GPa initial length…

Q: Consider the effect of wires hung on poles in which the left wire made an angle 29° below the…

A: Given, Tension=114N

Q: A disk between vertebrae in the spine is subjected to a shearing force of 570 N. Find its shear…

A: The expression for the shear deformation, S=FL0∆xπd24∆x=4FL0πSd2

Q: A steel wire of length 2.08 m with circular cross section must stretch no more than 0.200 cm when a…

A: Given data, Force F=380 N Length L0=2.08 m Young's modulus Y=2×1011 Pa Change in length ∆L=0.2×10-2…

Q: A 18 cm long tendon was found to stretch 5.4 mm by a force of 14.0 N. The tendon was approximately…

A:

Q: The total cross-sectional area of the load-bearing calcified portion of the two forearm bones…

A: Given that -  Mass Velocity Cross sectional area To Find - We have to determine the required…

Q: A disk between vertebrae in the spine is subjected to a shearing force of 700 N. Find its shear…

A: Data Given ,  Force ( F ) = 700 N Length of the cylinder ( L ) = 0.700 cm         = 0.700 × 10-2 m…

Q: Suppose a person’s femoral diaphysis is idealized as a circular cylinder with a periosteal diameter…

A:

Q: As an oil well is drilled, each new section of drill pipe supports its own weight and that of the…

A: the total weight of the pipe is F=weight of the pipe+weight of the drill bit=m'L0+l+mg=23kg/m3000…

Q: The figure shows the stress-strain curve for a material. The scale of the stress axis is set by…

A: Given :  scale of the stress axis is set  as s=320 in a unit of 106N/m2 ε=0.0090

Q: Problem 12:   Consider the effect of wires hung on poles in which the left wire made an angle 29°…

A:

Q: The figure shows an approximate plot of stress versus strain for a spider-web thread, out to the…

A: We  have,  stress=forcearea and                strain=change in lengthoriginal lengthHence,  work…

Mechanical Properties of Solids

There are three types of matter- solid, liquid and gas. Out of them, solids have a rigid shaped and size. The intermolecular forces of attractions in solids are greatest. Mechanical properties are the physical properties of a material which it shows, when it is provided with certain amount of force or load. These properties are to be kept in mind for various purposes. When a force is applied to an object, the object may or may not get deformed depending upon its elastic property. But every time the object develops a restoring force against the force applied. This is commonly known as stress. If the object changes its dimensions due to the force applied it develops strain ( which is the ratio of change in dimension to the original dimension).