A disk between vertebrae in the spine is subjected to a shearing force of 570 N. Find its shear deformation taking it to have the shear modulus of 1.00  109 N/m2. The disk is equivalent to a solid cylinder 0.700 cm high and 3.80 cm in diameter. (answer in m)

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Q: A disk between vertebrae in the spine is subjected to a shearing force of 700 N. Find its shear…

A: Data Given ,  Force ( F ) = 700 N Length of the cylinder ( L ) = 0.700 cm         = 0.700 × 10-2 m…

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A:

Q: A disk between vertebrae in the spine is subjected to a shearing force of 670 N. Find its shear…

A: The shear modulus is

Q: A disk between vertebrae in the spine is subjected to a shearing force of 630 N. Find its shear…

A: A disk between vertebrae in the spine is subjected to a shearing force of F = 630 N. Find its shear…

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Q: Please no hand writing solution

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Q: A disk between vertebrae in the spine is subjected to a shearing force of 600 N. Find its shear…

A:

Mechanical Properties of Solids

There are three types of matter- solid, liquid and gas. Out of them, solids have a rigid shaped and size. The intermolecular forces of attractions in solids are greatest. Mechanical properties are the physical properties of a material which it shows, when it is provided with certain amount of force or load. These properties are to be kept in mind for various purposes. When a force is applied to an object, the object may or may not get deformed depending upon its elastic property. But every time the object develops a restoring force against the force applied. This is commonly known as stress. If the object changes its dimensions due to the force applied it develops strain ( which is the ratio of change in dimension to the original dimension).