A die is tossed 396 times with the results below. X 1 2 4 6. f 56 77 72 57 54 80 Is this a balanced die? Use a 0.01 level of significance. Click here to view page 1 of the table of critical values of the chi-squared distribution. Click here to view page 2 of the table of critical values of the chi-squared distribution. Identify the null and alternative hypotheses. O A. Ho: The die is not balanced (none of the faces occur with the same frequency). H1: The die is balanced (all faces occur with the same frequency). O B. Ho: The die is balanced (all faces occur with the same frequency). H,: The die is not balanced (the faces do not all occur with the same frequency). O C. Ho: The die is balanced (all faces occur with the same frequency). H,: The die is not balanced (none of the faces occur with the same frequency). O D. Ho: The die is not balanced (the faces do not all occur with the same frequency). H: The die is balanced (all faces occur with the same frequency). Find the test statistic. (Round to two decimal places as needed.) What is the appropriate conclusion for this test?

A die is tossed 396 times with the results below. X 1 2 4 6. f 56 77 72 57 54 80 Is this a balanced die? Use a 0.01 level of significance. Click here to view page 1 of the table of critical values of the chi-squared distribution. Click here to view page 2 of the table of critical values of the chi-squared distribution. Identify the null and alternative hypotheses. O A. Ho: The die is not balanced (none of the faces occur with the same frequency). H1: The die is balanced (all faces occur with the same frequency). O B. Ho: The die is balanced (all faces occur with the same frequency). H,: The die is not balanced (the faces do not all occur with the same frequency). O C. Ho: The die is balanced (all faces occur with the same frequency). H,: The die is not balanced (none of the faces occur with the same frequency). O D. Ho: The die is not balanced (the faces do not all occur with the same frequency). H: The die is balanced (all faces occur with the same frequency). Find the test statistic. (Round to two decimal places as needed.) What is the appropriate conclusion for this test?

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Description: A die is tossed 396 times with the results below.1246.f567772575480Is this a balanced die? Use a 0.01 level of significance.Click here to view page 1 of the table of critical values of the chi-squared distribution.Click here to view page 2 of the ta

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Cadmium, a heavy metal, is toxic to animals. Mushrooms, however, are able to absorb and accumulate cadmium at high concentrations. Some governments have a safety limit for cadmium in dry vegetables at 1.9 parts per million (ppm). A hypothesis test is to be performed to decide whether the mean cadmium level in a certain mushroom is less than the government's recommended limit. Complete parts (a) through (c) below. a. Determine the null hypothesis. HoiH ppm (Type an integer or a decimal. Do not round.)
At the distribution hub of a major grocery store chain, a large shipment of honeydew melons has arrived. A worker chooses a random sample of 8 of the melons and records their weights (in kg) as shown below. 1.5, 2.8, 2.2, 3.5, 0.9, 2.5, 4.2, 3.2 Send data to Excel (a) Graph the normal quantile plot for the data. To help get the points on this plot, enter the data into the table in the correct order for a normal quantile plot. Then select "Compute" to see the corresponding area and z-score for each data value. Send data to calculator Index Data value Area 2-score 1 2 3 4 5 6 7 $ D D Compute 田

You are interested in investigating whether the type of computer a person primarily uses and the type of car they drive are dependent. The table below shows the results of a survey. α = 0.01 significance level. Sedan SUV Truck Tablet 100 95 60 Notebook 119 106 37 Desktop 112 103 27 The test-statistic for this data =_____ (Please show your answer to three decimal places.) The p-value for this sample =_____ (Please show your answer to four decimal places.)
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Do Predicted Temperatures match Actual Temperatures? The table shows the predicted and actual temperatures for a seven day period. Assume that the two samples are randomly selected. At the 0.1 significance level, test the claim that there is no mean difference in the predicted and actual temperatures.(Be sure to subtract in the same direction). Predicted Temperatures ⁰F Actual Temperatures ⁰F Difference ⁰F 81 76 75 79 86 83 85 90 82 82 77 78 78 80 What are the correct hypotheses? (Select the correct symbols and values.)H0: Select an answer p μ₁ s₁² μ(d) σ₁² x̄₂ μ x̄₁ ? < = > ≥ ≠ ≤ Select an answer s₁² μ 0 σ₁² μ₂ μ₁ x̄₁ p x̄₂ H1: Select an answer μ₂ x̄₁ x̄₂ p μ s₂² μ₁ μ(d) σ₂² ? ≤ ≠ > ≥ < = Select an answer μ₂ x̄₂ μ 0 σ₁² x̄₁ μ₁ p s₁² Original Claim = Select an answer H₁ H₀ df = Based on the hypotheses, find the following: Test Statistic = (Round to three decimal places.)Critical value(s) = ±± (Round to three decimal…
use the output below (equal variances not assumed) to determine if there is a significant difference in writing scores between women and men with t0 = -3.656 by stating your decision and write a concluding sentence
Mean 1001 206 Levene's Test for Equality of Variances Sig. 15.578 <.001 .510 1.402 df Sig. (2-tailed) 1205 .014 261.832 035 -3.168 -3.168 Std. Error Difference 3. Do Whites spend a significantly different amount of time on the internet (WWWHR) than Blacks? Group Statistics Std. Error Race of respondent N Std. Deviation Mean Www.hours per week WHITE 13.29) (16.124) BLACK 16.46 20.120 Independent Samples Test t-test for Equality of Means Mean t Difference Www hours per week -2.455 Equal variances assumed -2.124 Equal variances not assumed 1.291 1.492 95% Confidence Interval of the Difference Lower Upper -5.701 -6.106 -.636 -.231
Statistics students believe that the mean score on a first statistics test is 65. The instructor thinks that the mean score is higher. She samples 10 statistics students and obtains the scores: Grades 69 69 63.9 68.4 62.7 73.5 73.5 64.3 Test grades are believed to be normally distributed. Use a significance level of 5%. A. State the alternative hypothesis: HA: Ομ 65 B. State the mean of the sample: C. State the standard error of the sample means: D. State the test statistic: t = E. State the p-value: F. Decision: O Fail to reject the null hypothesis. Reject the null hypothesis. 73.5 96
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A supplier of digital memory cards claims that no more than 1% of the cards are defective. In a random sample of 600 memory cards, it is found that 3% are defective, but the supplier claims that this is only a sample fluctuation. How many populations? 01 What is the parameter? O tandard Deviation Variance Difference between Means Proportion Mean
H1 H2 A study was done using a treatment group and a placebo group. The results are shown in the table. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Use a 0.10 significance level for both parts. 25 36 2.37 2.69 s 0.69 0.96 a. Test the claim that the two samples are from populations with the same mean. What are the null and alternative hypotheses? O A. Ho: H1 <#2 H: H1 2 42 VB. Họ: H1 = P2 H: 1 42 O C. Ho: H1 #H2 O D. Ho: H1 = H2 H: 41
After the political ad campaign, pollsters check the mayor's positives. They test the hypothesis that the ads produced no change against the alternative that the positives are now above 47% and find a P-value of 0.283. Which conclusion is appropriate? Explain. Choose the correct answer below. O A. There is a 28.3% chance that natural sampling variation could produce poll results at least as far above 47% as these if there is really no change in public opinion. There is a 28.3% chance that the poll they conducted is correct. O B. O C. There is a 71.7% chance that the ads worked. O D. There is a 28.3% chance that the ads worked.