(a) Determine the moment of force F about point C. (b) Determine the perpendicular distance (d) between point C and the line of action of force F.
(a) Determine the moment of force F about point C. (b) Determine the perpendicular distance (d) between point C and the line of action of force F.
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Question
![PROBLEM 2:
(a) Determine the moment of force F about
point C.
(b) Determine the perpendicular distance (d)
between point C and the line of action of
force F.
2 m
B
F = 500 N
3 m
TCA
4 m
C](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F244951d7-5ea5-470e-a70a-afadd17f5c7d%2F67bd838a-8a5b-47ce-9151-c948404dac99%2Fx6ckyj_processed.png&w=3840&q=75)
Transcribed Image Text:PROBLEM 2:
(a) Determine the moment of force F about
point C.
(b) Determine the perpendicular distance (d)
between point C and the line of action of
force F.
2 m
B
F = 500 N
3 m
TCA
4 m
C
![F123 E5C+ 30.127 +[-w8.66+39.91j
%3D
25.12 -1ュ.4911Fュ23|= 27.57N
%3D
Problem 4:
☺ = -24.43
%3D
Three ropes are attached to the post at A in Fig. (a). The forces in the ropes are
260 lb, F2 = 75 lb, and F3
Fi = =
force R that is equivalent to the three forces shown, and (2) the coordinates of the
point where the line of action of R intersects the yz-plane.
60 lb. Determine (1) the magnitude of the
%3D
%3D
F=E(218)= 260lb-.23 -95
Fq -59.8 -239.
12 ft
F21
3 +.38
F1
2-.12:5 +,33 lt 4ft|
Sa109-
R-(-59.830)
B)intkesecls
Sh- で6Eて-)
(a)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F244951d7-5ea5-470e-a70a-afadd17f5c7d%2F67bd838a-8a5b-47ce-9151-c948404dac99%2Fi9zm8sbq_processed.jpeg&w=3840&q=75)
Transcribed Image Text:F123 E5C+ 30.127 +[-w8.66+39.91j
%3D
25.12 -1ュ.4911Fュ23|= 27.57N
%3D
Problem 4:
☺ = -24.43
%3D
Three ropes are attached to the post at A in Fig. (a). The forces in the ropes are
260 lb, F2 = 75 lb, and F3
Fi = =
force R that is equivalent to the three forces shown, and (2) the coordinates of the
point where the line of action of R intersects the yz-plane.
60 lb. Determine (1) the magnitude of the
%3D
%3D
F=E(218)= 260lb-.23 -95
Fq -59.8 -239.
12 ft
F21
3 +.38
F1
2-.12:5 +,33 lt 4ft|
Sa109-
R-(-59.830)
B)intkesecls
Sh- で6Eて-)
(a)
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