A uniform rectangular block has mass M and sides 2a, 2b and 2c. Find the principal moments of inertia of the block (i) at its centre of mass, (ii) at the centre of a face of area 4ab. Find the moment of inertia of the block (i) about a space diagonal, (ii) about a diagonal of a face of area 4ab.
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A uniform rectangular block has mass M and sides 2a, 2b and 2c. Find the principal moments of inertia of the block (i) at its centre of mass, (ii) at the centre of a face of area 4ab. Find the moment of inertia of the block (i) about a space diagonal, (ii) about a diagonal of a face of area 4ab.
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- Assume that (1) F = 10i +60j - 20k, acting at a point (8, 6, 4), and (2) two end points of a line L are A (2, 0, 4) and B (-7, 6, 2), respectively. Determine the moment of the force F about the line L. In the figure (a) is a force F and line L. (b) is the position vector r from A to the point of application of F.In the figure, a 18 kg block is held in place via a pulley system. The person's upper arm is vertical; the forearm makes angle θ = 30° with the horizontal. Forearm and hand together have a mass of 2.1 kg, with a center of mass at distance d1 = 12 cm from the contact point of the forearm bone and the upper-arm bone (humerus). The triceps muscle pulls vertically upward on the forearm at distance d2 = 2.6 cm behind that contact point. Distance d3 is 34 cm. Take the upward direction to be positive. What are the forces on the forearm from (a) the triceps muscle and (b) the humerus?In the figure, a 18 kg block is held in place via a pulley system. The person's upper arm is vertical; the forearm makes angle θ = 30° with the horizontal. Forearm and hand together have a mass of 2.1 kg, with a center of mass at distance d1 = 12 cm from the contact point of the forearm bone and the upper-arm bone (humerus). The triceps muscle pulls vertically upward on the forearm at distance d2 = 2.6 cm behind that contact point. Distance d3 is 34 cm. Take the upward direction to be positive. What are the forces on the forearm from (a) the triceps muscle and (b) the humerus?
- - A 1.00 kg particle with velocity ✓ = (4.28 m/s )î – (7.79 m/s ) is at x = 8.75 m, y = 3.55 m. It is pulled by a 3.50 N force in the negative x direction. About the origin, what are (a) the particle's angular momentum, (b) the torque acting on the particle, and (c) the rate at which the angular momentum is changing? (a) Number i (b) Number i (c) Number i k Units k Units k UnitsHint: The cube undergoes an inelastic colli- sion at its bottom left edge. Note: The moment of inertia of this cube (with edges of length 2 a and mass M) about 2 8 Μα? an axis along one of its edges is 3 A solid cube is sliding on a frictionless sur- face with uniform velocity v,min. The cube hits a small obstacle on the table, which causes the cube to tilt (as shown in the figure below). E 2 a Umin M M g Find the minimum value of vmin such that the cube falls over on its front face.The moment of inertia I of a cheap door of mass M = 4.00 kg (about an axis going through the hinges at the door frame) is I= (1/3) M · R², where R= 0.960 m is the width of the door. The door is initially open and at rest. The door suddenly is struck by a huge and heavy dart of mass m = 0.300 kg traveling perpendicular to the plane of the door at a speed vi = 20.0 m/s. The dart perforates the wooden door getting permanently stuck at the point of impact, which happened to be right next to the free vertical edge of the door (close to the handle). Because the dimensions of the dart are so small (even though they are exaggerated in the picture for clarity) compared to its distance R to the rotational axis (the distance from the hinge to the free vertical edge next to which the dart strikes the door, which is the width of the door R) we can treat the dart as a point mass. I remind you that we learned in class that the moment of inertia of a point mass is I, = m-R², where R is the…
- Take an equilateral triangular sheet of side, and remove the "middle" triangle (1/4 of the area). Then remove the "middle" triangle from each of the remaining three triangles, and so on, forever. Let the final object have mass. The moment of inertia of final object about axis passing through 'O' and perpendicular to plane of object is ml²/x. Then the value of x isA 117 kg horizontal platform is a uniform disk of radius 1.67 m and can rotate about the vertical axis through its center. A 62.7 kg person stands on the platform at a distance of 1.11 m from the center, and a 29.5 kg dog sits on the platform near the person 1.39 m from the center. Find the moment of inertia of this system, consisting of the platform and its population, with respect to the axis. moment of inertia: kg · m?Four point masses, m¡ = 2 kg, m2 = 3 kg, m3 = 4 kg and m4 5 kg are on the x axis as shown in the figure below. mi m2 m3 1.0 2.0 3.0 4.0 x (m) Find the moment of inertia of the above system about an axis of rotation that is perpendicular to the page and passes through x = 4 m. Find the moment of inertia of the above system about an axis of rotation that is perpendicular to the page and passes through x = 3 m.
- Two kids, each with a mass of 25.0 kg, are standing at the edge of a merry-go-round. Treat both kids as point masses. The merry-go-round is a uniform disk with a mass of 97.5 kg and a radius of 1.25 meters, which is free to rotate about its center of mass without friction. The moment of inertia of a solid disk rotating about its center of mass is given by I = MR2 /2 , and the moment of inertia of a point mass is given by I = mr2 . The merry go round is initially rotating at 12.5 revolutions per minute (rpm). a) If both kids walk to the center of the merry-go-round, what will the final angular speed be, in rpm? Hint: use conservation of angular momentum. b) What is the change in the total kinetic energy of the disk and the two kids during this process? Give your answer in units of Joules (J)John McClane, desperately trying to escape the bad guys in an upper floor of a skyscraper, grabs a fire hose and crashes out a window. He falls toward the ground, dragging the hose with him. The hose is wound around a cylinder that has a moment of inertia equal to 5 kg m2, and the hose unspools from the cylinder as McClane falls. Assuming that the hose is pulled from the cylinder at an angle that is perpendicular to the cylinder's radius, what is McClane's acceleration? Let McClane's mass be 75 kg and the radius of the cylinder be 0.5 m. Neglect friction and air resistance. Hose Wall Spool McClaneProblem 3: Suppose we want to calculate the moment of inertia of a 65.5 kg skater, relative to a vertical axis through their center of mass. Part (a) First calculate the moment of inertia (in kg m2) when the skater has their arms pulled inward by assuming they are cylinder of radius 0.11 m. sin() cos() tan() 7 8 9 HOME cotan() asin() acos() E 4 5 atan() acotan() sinh() 1 3 cosh() tanh() cotanh() END ODegrees O Radians Vol BACKSPACE DEL CLEAR Submit Hint Feedback I give up! Part (b) Now calculate the moment of inertia of the skater (in kg m?) with their arms extended by assuming that each arm is 5% of the mass of their body. Assume the body is a cylinder of the same size, and the arms are 0.825 m long rods extending straight out from the center of their body being rotated at the ends.