A credit card spending study shows that people tend to spend more when paying with a credit card instead of cash. A well known bank wants to verify the result of this study and estimated the average credit card spending of its customers by two 90% confidence intervals: (9000, 10000) and (9100, 9900). The two intervals were calculated from the same data and based on the z-distribution or the t-distribution. Which confidence interval was based on the t-distribution? (9100 , 9900) because it is the narrowest interval Not enough information to answer the question (9000, 10000) because it is the widest interval
A credit card spending study shows that people tend to spend more when paying with a credit card instead of cash. A well known bank wants to verify the result of this study and estimated the average credit card spending of its customers by two 90% confidence intervals: (9000, 10000) and (9100, 9900). The two intervals were calculated from the same data and based on the z-distribution or the t-distribution. Which confidence interval was based on the t-distribution? (9100 , 9900) because it is the narrowest interval Not enough information to answer the question (9000, 10000) because it is the widest interval
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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A credit card spending study shows that people tend to spend more when paying with a credit card instead of cash. A well known bank wants to verify the result of this study and estimated the average credit card spending of its customers by two 90% confidence intervals: (9000, 10000) and (9100, 9900). The two intervals were calculated from the same data and based on the z-distribution or the t-distribution. Which confidence interval was based on the t-distribution?
(9100 , 9900) because it is the narrowest interval
Not enough information to answer the question
(9000, 10000) because it is the widest interval
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