A copper pipe with the diameter of 5 cm and surface temperature of 75 C is exposed to atmospheric air at 10 C. A) Find the rate of heat loss per unit of length on a calm day B) Find the rate of heat loss per unit of length on a breezy day when the wind speed is 5 m/s
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- A person wearing a heavy parka is standing in a cold wind. Describe the modes of heat transfer determining heart loss from the person's body.Using Table 1.4 as a guide, prepare a similar table showing the orders of magnitude of the thermal resistances of a unit area for convection between a surface and various fluids.The chill felt on a cold windy day is related to the increase in the heat transfer coefficient between the body skin and the surrounding atmosphere. Let's consider a 3mm thick oily skin layer, the inner surface of which is kept at 360C. On a calm day, the heat transfer coefficient on the outer surface reaches 65W / m2K with a wind speed of 25W / m2K 30km / h.a) What is the ratio of the heat lost from the unit area of the skin on the calm day to the windy day.b) What will be the outer surface temperature of the skin on a calm day? What is this for the windy day.c) What should be the temperature of the air in a calm day to obtain the equivalent of the heat loss at -150C air temperature on a windy day?
- Fluid fluid with a temperature of -20C passes through a copper cylindrical wire. The outer diameter of the wire is 10 mm. The wire is in contact with air at a temperature of 25C, which is h = 50 W / m2K. The heat conduction coefficient of the wire is k = 0.5 W / mK. It will be applied in different thicknesses. a) Calculation separately for the resulting heat transfer per m when 0, 2.5, 5 and 7.5 m are applied. b) To interpret which thickness will increase the heat transfer by calculating the critical diameter. c) Graph the insulation and heat transfer rate against each other.Heat transfer1) "Two-by-four" wood studs have actual dimensions of 4. 13 x 9.21 cm and a thermal conductivity of 0.1 W/m. °C. A typical wall for a house is constructed as shown below. Calculate: a) heat transfer rate through the wall, b) temperature of inside wall, outside wall, and insulation material; and (c) temperature drop across common brick. Disregard any contact resistances at interfaces. Outside air convection, h = 15 W/m?. °C Common brick, k= 0.69 8 cm 1.9 cm, k = 0.96 Gypsum sheath 1.9 cm. k= 048 40.6 cm Insulation, k = 0.04 2 x 4 studs Inside air convection, h= 7.5 W/m²• C
- find only the following What is the total heat transfer to/from the building?A wooden sphere of diameter 5 cm is initially at a uniform temperature of 21 °C. Its surfacetemperature is suddenly raised to 83 °C. The thermal conductivity and thermal diffusivity ofthe wood are 0.15 W/m K and 0.82 x 10-7 m^2/s, respectively. a) Calculate the temperature 2 cm beneath the surface of the sphere 30 min after the sudden increase in temperature.b) Calculate the energy gained by the sphere during this time.[2] A reservoir of hot water kept at 380K is well insulated except for a copper rod with a cross sectional area of 0.25 m? and a length of 0.50 meters. The rod is also well insulated except for its ends and the other end is in a second well insulated reservoir of water held at 280K. a) Determine the rate of heat flow through the copper rod. b) Calculate the temperature at the center of the rod (0.25 meters from either end). Then extend the process to find the temperature at each point 0.1m along the rod. c) Calculate the rate of entropy change at each end of the rod. d) Using your answer for (c), show that the statements "Heat flows spontaneously from high temperature to low temperature." and "Any spontaneous process causes the entropy of the universe to increase." are logically equivalent for situations with heat flow. e) Each reservoir of water holds 1 m of water. With a steady flow established, the power fails so that the heating and cooling of the water ceases. What are the…