"Two-by-four" wood studs have actual dimensions of 4. 13 x 9.21 cm and a thermal conductivity of 0.1 W/m. °C. A typical wall for a house is constructed as shown below. Calculate: a) heat transfer rate through the wall, b) temperature of inside wall, outside wall, and insulation material; and (c) temperature drop across common brick. Disregard any contact resistances at interfaces. Outside air convection, h = 15 W/m.C Common brick, k= 0.69 8 cm 1.9 cm, k= 0.96 Gypsum sheath 19 cm, k= 0.48 -40.6 cm - -Insulation, k = 0.04 - 2x 4 studs Inside air convection, h = 7.5 W/m• 'C

Elements Of Electromagnetics
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1) "Two-by-four" wood studs have actual dimensions of 4. 13 x 9.21 cm and a thermal
conductivity of 0.1 W/m. °C. A typical wall for a house is constructed as shown
below. Calculate: a) heat transfer rate through the wall, b) temperature of inside wall,
outside wall, and insulation material; and (c) temperature drop across common brick.
Disregard any contact resistances at interfaces.
Outside air convection, h = 15 W/m?. °C
Common brick, k= 0.69
8 cm
1.9 cm, k = 0.96
Gypsum
sheath
1.9 cm. k= 048
40.6 cm
Insulation, k = 0.04
2 x 4 studs
Inside air convection, h= 7.5 W/m²• C
Transcribed Image Text:1) "Two-by-four" wood studs have actual dimensions of 4. 13 x 9.21 cm and a thermal conductivity of 0.1 W/m. °C. A typical wall for a house is constructed as shown below. Calculate: a) heat transfer rate through the wall, b) temperature of inside wall, outside wall, and insulation material; and (c) temperature drop across common brick. Disregard any contact resistances at interfaces. Outside air convection, h = 15 W/m?. °C Common brick, k= 0.69 8 cm 1.9 cm, k = 0.96 Gypsum sheath 1.9 cm. k= 048 40.6 cm Insulation, k = 0.04 2 x 4 studs Inside air convection, h= 7.5 W/m²• C
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