A constant electric field with magnitude 1.50 ✕ 103 N/C is pointing in the positive x-direction. An electron is fired from  x = −0.0200 m  in the same direction as the electric field. The electron's speed has fallen by half when it reaches  x = 0.170 m,  a change in potential energy of 4.56 ✕ 10−17 J. The electron continues to  x = −0.250 m  within the constant electric field. If there's a change in potential energy of −1.01 ✕ 10−16 J as it goes from  x = 0.170 m  to  x = −0.250 m,  find the electron's speed (in m/s) at  x = −0.250 m.

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Chapter1: Units, Trigonometry. And Vectors
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A constant electric field with magnitude 1.50 ✕ 103 N/C is pointing in the positive x-direction. An electron is fired from 

x = −0.0200 m

 in the same direction as the electric field. The electron's speed has fallen by half when it reaches 

x = 0.170 m,

 a change in potential energy of 4.56 ✕ 10−17 J. The electron continues to 

x = −0.250 m

 within the constant electric field. If there's a change in potential energy of −1.01 ✕ 10−16 J as it goes from 

x = 0.170 m

 to 

x = −0.250 m,

 find the electron's speed (in m/s) at 

x = −0.250 m.
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