A uniform electric field has a magnitude 2.40 kV/m and points in the +x direction. (a) What is the electric potential difference between x = 0.00 m plane and the x = 3.70 m plane? V(3.70 m) = kV (b) A point particle that has a charge of +2.60 µC is released from rest at the origin. What is the change in the electric potential energy of the particle as it travels from the x = 0.00 m plane to the x = 3.70 m plane? Δυ- m) (c) What is the kinetic energy of the particle when it arrives at the x = 3.70 m plane? K3.70 m = m) (d) Find the expression for the electric potential V(x) if its value is chosen to be zero at x = 0. (Use the following as necessary: x.) V(x) = kV

A uniform electric field has a magnitude 2.40 kV/m and points in the +x direction. (a) What is the electric potential difference between x = 0.00 m plane and the x = 3.70 m plane? V(3.70 m) = kV (b) A point particle that has a charge of +2.60 µC is released from rest at the origin. What is the change in the electric potential energy of the particle as it travels from the x = 0.00 m plane to the x = 3.70 m plane? Δυ- m) (c) What is the kinetic energy of the particle when it arrives at the x = 3.70 m plane? K3.70 m = m) (d) Find the expression for the electric potential V(x) if its value is chosen to be zero at x = 0. (Use the following as necessary: x.) V(x) = kV

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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