A composite shaft ABCD made of three parts is placed between two walls, as shown in Fig. 7. Part AB is a hollow steel shaft having an outer diameter of dAB and a thickness of 0.3dAB. Part BC is a solid steel shaft having a diameter of dac. Part CD is a solid bronze shaft having a diameter of dcp. The shaft ABCD is fixed to the wall at A. The gap between D and the rigid wall E is initially 0.20 mm. • Determine the support reactions at A and E when the forces PB B KN and PD = 3ß kN are applied to the shaft, and the temperature of the shaft is increased by 25°C. Draw force diagrams relevant to the problem and condition to induce reaction at support E. • Find also the maximum stress in the shaft ABCD. Use: Shaft lengths: LAB B cm, LBC 2B cm and LCD B cm Shaft diameters: dAB 2B mm, dBC B mm, and dcD B mm Material properties: Modulus of elasticity: Esteel = 210 GPa, Ebronze = 100 GPa Co-efficient of thermal expansion: asteel = 11.9x106/"C; abronze =16.9x10-6/C

A composite shaft ABCD made of three parts is placed between two walls, as shown in Fig. 7. Part AB is a hollow steel shaft having an outer diameter of dAB and a thickness of 0.3dAB. Part BC is a solid steel shaft having a diameter of dac. Part CD is a solid bronze shaft having a diameter of dcp. The shaft ABCD is fixed to the wall at A. The gap between D and the rigid wall E is initially 0.20 mm. • Determine the support reactions at A and E when the forces PB B KN and PD = 3ß kN are applied to the shaft, and the temperature of the shaft is increased by 25°C. Draw force diagrams relevant to the problem and condition to induce reaction at support E. • Find also the maximum stress in the shaft ABCD. Use: Shaft lengths: LAB B cm, LBC 2B cm and LCD B cm Shaft diameters: dAB 2B mm, dBC B mm, and dcD B mm Material properties: Modulus of elasticity: Esteel = 210 GPa, Ebronze = 100 GPa Co-efficient of thermal expansion: asteel = 11.9x106/"C; abronze =16.9x10-6/C

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

4
Figure shows a two-arm robot manipulator. The lengths of the arms are 5 and 7 m, respectively. Determine the range of angles that can cover the quadrant working area by avoiding the square block shown. Use the variational approach. 13- 12- 11- 10- K • e 0, 12345 6 7 8 9 10 11 12 13 14 15
Please solve analytically!!!
Solve; y" +4y' + 3y = 0 y(0) = 3 & y'(0) = 1 %3D
Use the graphical method to solve the problem
Please be careful with the decimal
53 B 36 19 a = 30° B = 79⁰ Y = 0° 0 = 81° 36 radius Find the velocity and acceleration of the bicycle. 4 bar linkage problem. 60deg/s constant CCW angular velocity of the rider's thigh (upper leg), solve the mechanism kinematics and find the bicycle linear velocity and acceleration at this instant. Assume the gear ratio of the bicycle is 1.5. Hint: Use a fixed axis kinematics method with the x- axis along the 61 cm frame from the crank center to rider's pelvis.
The Maclaurin expansion of f(x) = e-5* is (-1)"x" 5"n! n=0 as above. O None of these +00 (-1)"5"x" 57x" n! n! n3D0 レ

Let f(x) = √√√x, g(x) = x + 8 and h(x) = . Compute the following function X (fh)(4)
Battleships! In 1905, as part of the Russo-Japanese War, the Imperial Japanese Navy (IJN) under the command of Admiral Togo engaged the Russian fleet under the command of Admiral Rozhestvensky in the Battle of Tsushima. This was the first major naval engagement to be dominated by "big guns." In this question we will model the 12" Armstrong Whitworth guns employed by the IJN. The guns are capable of firing a 390kg shell at a speed of 732ms-1. For simplicity, we shall assume that this shell is a sphere of diameter D such that the drag due to air resistance can be approximated as 1 FD CopAv² where Cp = 1/2 is the approximate drag coefficient for a sphere, A = T(D/2)2 is the reference area, p - 1.225kgm-3 is the density of air at sea level, and v is the velocity, whence C = 16 pD? The overall force experienced by our shell in flight is hence F = mg – cvv , where m is the mass of the shell and g is the acceleration due to gravity, v= v and v^ = v/v, with v corresponding to the velocity…
Find the transformation matrix for the following rotations: 1) Rotate a about the original x-axis (in frame 0). (Xo, Yo, Zo) → (X₁,Y₁,Z₁); 2) Followed by a rotation of B about current z-axis (in frame 1). (X₁,Y₁,Z₁)→ (X₂, X₂, Z₂); 3) Followed by a rotation of y about Xo -axis (in frame 0). (X2, Y, Z₂)→ (X3, Y, Z3); 4) Followed by a rotation of about Z3 - axis (in frame 3). (X3, X3,Z3) → (X,Y4, Z4). E F3 $ R F F4 Q Search DII % 5 F5 T F6 6 Y PRE F7 & H 7 PrtScn F8 U 8 Home End
Q6) A resolver output shown in Figure 4. Find the shaft angle if 1-1, then draw the output if the shaft angle is 190. SM 10 -12 14 12 10 WW -14 0125 025 0375 05 0625 075 0875 (sec) Figure 4