A company manufactures printers and fax machines at plants located in Atlanta, Dallas, and Seattle. To measure how much employees at these plants know about quality management, a random sampleof 6 employees was selected from each plant and the employees selected were given a quality awareness examination. The examination scores for these 18 employees are shown in the following table.The sample means, sample variances, and sample standard deviations for each group are also provided. Managers want to use these data to test the hypothesis that the mean examination score is thesame for all three plants.Plant 1Plant 2Plant 3AtlantaDallasSeattle847260747463827461777568726876858168Sample797466meanSamplevariance29.618.035.6Samplestandard5.444.245.97deviationSet up the ANOVA table for these data. (Round your values for MSE and F to two decimal places, and your p-value to four decimal places.)SourceSumDegreesof FreedomMeanFp-valueof Variationof SquaresSquareTreatmentsErrorTotalTest for any significant difference in the mean examination score for the three plants. Use = 0.05. Test for any significant difference in the mean examination score for the three plants. Use a = 0.05.State the null and alternative hypotheses.Hoi H1# Hz # H3Hai H1 = Hz = H3Ho: Not all the population means are equal.Hai H1 = H2 = H3Ho: At least two of the population means are equal.H: At least two of the population means are different.Ho: H1 = H2 = H3Ha: H1# Hz# H3Ho: H1 = H2 = H3H: Not all the population means are equal.Find the value of the test statistic. (Round your answer to two decimal places.)Find the p-value. (Round your answer to four decimal places.)p-value =State your conclusion.Do not reject Ho. There is not sufficient evidence to conclude that the means for the three plants are not equal.Do not reject Ho. There is sufficient evidence to conclude that the means for the three plants are not equal.Reject Ho. There is sufficient evidence to conclude that the means for the three plants are not equal.Reject Ho. There is not sufficient evidence to conclude that the means for the three plants are not equal.Submi+ AngO O O O

Use EXCEL to obtain the ANOVA table. Follow the instruction to obtain the values for table in…

A company manufactures printers and fax machines at plants located in Atlanta, Dallas, and Seattle. To measure how much employees at these plants know about quality management, a random sample of 6 employees was selected from each plant and the employees selected were given a quality awareness examination. The examination scores for these 18 employees are shown in the following table. The sample means, sample variances, and sample standard deviations for each group are also provided. Managers want to use these data to test the hypothesis that the mean examination score is the same for all three plants. Plant 1 Plant 2 Plant 3 Atlanta Dallas Seattle 84 72 60 74 74 63 82 74 61 77 75 68 72 68 76 85 81 68 Sample 79 74 66 mean Sample variance 29.6 18.0 35.6 Sample standard deviation 5.44 4.24 5.97

A company manufactures printers and fax machines at plants located in Atlanta, Dallas, and Seattle. To measure how much employees at these plants know about quality management, a random sample of 6 employees was selected from each plant and the employees selected were given a quality awareness examination. The examination scores for these 18 employees are shown in the following table. The sample means, sample variances, and sample standard deviations for each group are also provided. Managers want to use these data to test the hypothesis that the mean examination score is the same for all three plants. Plant 1 Plant 2 Plant 3 Atlanta Dallas Seattle 84 72 60 74 74 63 82 74 61 77 75 68 72 68 76 85 81 68 Sample 79 74 66 mean Sample variance 29.6 18.0 35.6 Sample standard deviation 5.44 4.24 5.97

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A company manufactures printers and fax machines at plants located in Atlanta, Dallas, and Seattle. To measure how much employees at these plants know about quality management, a random sample of 6 employees was selected from each plant and the employees selected were given a quality awareness examination. The examination scores for these 18 employees are shown in the following table. The sample means, sample variances, and sample standard deviations for each group are also provided. Managers want to use these data to test the hypothesis that the mean examination score is the same for all three plants. Plant 1 Atlanta Plant 2 Plant 3 Dallas Seattle 84 72 59 74 74 64 82 74 62 77 74 70 71 70 76 86 86 59 Sample 79 75 65 mean Sample variance 35.2 31.6 45.6 Sample standard deviation 5.93 5.62 6.75 Set up the ANOVA table for these data. (Round your values for MSE and F to two decimal places, and your p-value to four decimal places.) Source Sum Degrees of Freedom Mean F p-value of Variation…
In the Star and Tribune newspaper, there is an article entitled "1 in 8 school buses fail tests." The article says that the overall statewide proportion of school buses that fail safety tests is 9%. However, one bus company has a higher rate of over 12%. Assume that we want a new estimate for the statewide proportion of school buses that fail the safety inspection. We take a sample of 500 buses and find that 90 buses fail the safety inspection. Based on the new sample data, I construct this 90% confidence interval estimate for p: 152 < p < .208. Explain what this confidence interval means. O I am 90% sure that the number of buses that fail the inspection is between.152 and .208. O I am 95% sure that the true proportion of buses that fail the inspection is between .152 and .208. O I am 90% sure that the proportion of buses in this sample that fail the inspection is between .152 and .208. O I am 90% sure that the true proportion of buses that fail the inspection is between .152 and .208.
A marketing agency wanted to determine if a new commercial changed people's opinion about a company. They recruited n=30 participants to watch the commercial. First, everyone was givien a survey to determine their attitudes toward the company. Then, everyone watched the new commercial. Finally, they were given the same survey again and asked about their attitudes toward the comapny after seeing the commercial. The agency wanted to see if attitudes were changed by the commercial. What statistical test should they use?
A psychologist wanted to know if students in her class were more likely to cheat if they were low achievers. She divided her 60 students into three groups (low, middle, and high) based on their mean exam score on the previous three tests. She then asked them to rate how likely they were to cheat on an exam if the opportunity presented itself with a very limited chance for consequences. The students rated their desire to cheat on a scale ranging from 1-100, with lower numbers indicating less desire to cheat. Before opening the data, what would you hypothesize about this research question? Open the data set. Before running any statistical analyses, glance through the data. Do you think that your hypothesis will be supported? Conduct descriptive analyses and report them here. Conduct a one-way ANOVA. Report your statistical findings (including any applicable tables in APA format) here. What would you conclude from this analysis? What would be your next steps, if this…
If a researcher failed to use a random sample, how would this affect the research conclusion? If a researcher failed to use random assignment, how would this affect the research results?
As the plant operations manager for Oxford Biotech, you are responsible for monitoring the amount of product placed in each carton. To be consistent with package labeling, cartons should contain a mean of 368 grams of product. Thousands of cartons are produced during a shift, and weighing every single carton was determined to be too time-consuming, costly, and inefficient. Instead, a random sample of cartons is selected. Based on your analysis of the sample, you had to decide whether to maintain, alter, or shut down the process. In a prior question, you assumed a sample size of n = from a population with mean of 368 grams and standard deviation of 15, 25 was selected and you calculated the probability of selecting a sample with a mean of 365 grams or less. If a larger sample size is selected, the sample mean will be closer to the population mean. This result can be illustrated by calculating the probability of selecting a sample with a mean of 365 grams, if the sample size were…
A psychological study wants to analyze the relationship between anxiety and binge drinking; a questionnaire for anxiety and questionnaire for binge drinking is administered to each subject. What would be a good statistical test to test the hypothesis?
Here are 6 celebrities with some of the highest net worths (in millions of dollars) in a recent year: Oprah Winfrey (3200), Michael Jordan (1700), Paul McCartney (1200), J. K. Rowling (1000), David Copperfield (1000), and Jerry Seinfeld (950). Find the range, variance, and standard deviation for the sample data. What do the results tell us about the population of all celebrities? Based on the nature of the amounts, what can be inferred about their precision? The range is $ million. (Round to the nearest integer as needed.) ...
A nationwide job recruiting firm wants to compare the annual incomes for childcare workers in New York and Illinois. Due to recent trends in the childcare industry, the firm suspects that the that the mean annual income of childcare workers in the state of New York is greater than the mean annual income of childcare workers in Illinois. To see if this is true, the firm selected a random sample of 20 childcare workers from New York and an independent random sample of 20 childcare workers from Illinois and asked them to report their mean annual income. The data obtained were as follows. Annual income in dollars New York 46686 , 34979 , 47325 , 48892 , 51128 , 56792 , 47785 , 48995 , 57301 , 55176 , 48002 , 45718 , 50351 , 58527 , 47067 , 53699 , 54361 , 49727 , 36426 , 50870 Illinois 48009 , 46871 , 42774 , 49790 , 43163 , 45401 , 41068 , 50300 , 47064 , 42003 , 47775 , 41917…
In the US, 45.1% of all people have type O blood, 39.6% have type A blood, 10.9% have type B blood and 4.4% have type AB blood. A researcher wants to see if the distribution of blood type is different for millionaires. The table below shows the results of a random sample of 614 millionaires. What can be concluded at the significant level of a = 0.05. For this study, we should use Chi-Square test for Goodness of Fit Your friend Caroline helped you with the null and alternative hypotheses... Ho : The distributions of blood types are the same between the general population and the millionaires. Ha: The distributions of blood types are NOT the same between the general population and the millionaires. You drew 614 samples, and the observed frequencies are recorded below. Please complete the table (round answers to at least 4 decimal places). Blood Type 0 A B AB Observed Count 274 230 57 53 Expected Count Click Download CSV to download csv file of data or copy/paste the data into Excel.…
The College Board provided comparisons of Scholastic Aptitude Test (SAT) scores based on the highest level of education attained by the test taker's parents. A research hypothesis was that students whose parents had attained a higher level of education would on average score higher on the SAT. The overall mean SAT math score was 514. SAT math scores for independent samples of students follow. The first sample shows the SAT math test scores for students whose parents are college graduates with a bachelor's degree. The second sample shows the SAT math test scores for students whose parents are high school graduates but do not have a college degree. College Grads 485 487 518 517 650 542 570 426 566 499 588 562 497 448 592 453 High School Grads 442 492 580 478 479 425 486 485 528 390 524 535 (b) What is the point estimate of the difference between the means for the two populations? (c) Find the value of the test statistic. (Round your answer…
The Bureau of Labor Statistics reports that the official unemployment rate for Black people was 10.4% and 4.7% for White people in February 2015. Select all correct answers for this question. O The samples of white and black people are independent. The explanatory variable is the unemployment rate. The response variable is the unemployment rate. The response variable is race.